3. Determine the stress and strain in the cable on the upper beam
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- The force P is applied to the bar, which is made from an elastic perfectly plastic material. Construct a graph to show how the force in each section AB and BC (vertical axis) varies as P (horizontal axis) is increased. The bar has cross-sectional areas of 1 in2 in region AB and 4 in2 in region BC. Take sY = 30 ksi.Two fully loaded tractor trailers travel over the bridge putting substantial loading on the structure. As they pass over the middle of the bridge, one of the vertical supporting pillars, which is fixed at its bottom, deforms as shown below. The weight of the trucks causes point T to move to point T'—a distance of 2.5 cm along the x-axis. If the pillar has an original height of 27 m , find the shear strain at point T.The pole is supported by a pin at B and A-36 steel guy wire AC. If the wire has a diameter of 0.2. Modulus of Elasticity of Steel = 200GPA or 29x103 ksi Poisson's ratio of steel=0.321 a. Determine how much the wire stretches when the horizontal force acts on the pole. 3 ft 30 D 2.5 kip 4 ft B b. Determine the change in the wire's radius c. At what angle is the principal stresses on pole BC? Use Mohr's Circle. d. What is the principal stress in pol BC? Use Mohr's Circle e. Draw the stresses on a unit element acting on 35-degree clockwise direction of pole BC. Use Mohr's Circle. f. What are the principal stresses in point D? Use Mohr's Circle. (answer in ksi) g. At what angle is the principal stresses acting on point D? Use Mohr 's Circle. h. Draw the stresses on a unit element acting on 35degree-clockwise direction of point D. Use Mohr's Circle. (answer in ksi)
- The normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E where y = 2.3 lb/in.³ is the specific weight of the material, y = 2.4 in. is the distance from the free (i.e., bottom) end of the bar, L = 6 in. is the length of the bar, and E= 24000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length L of the bar (c) the maximum normal strain in the bar. Answer: (a) d = i (b) avg (c) Emax || MI Mi x10-6 in. με μεThe assembly is subjected to a tension force P = 2500 N. If these cables are arranged in a parallel assembly as shown, determine the stress of each cable. Cable Length (m) Area (sq. mm.) E (GPa) A 1.4 30 50 B 1.0 10 80 C 1.2 8 60The normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E where y=2.4 lb/in.³ is the specific weight of the material, y = 0.6 in. is the distance from the free (i.e., bottom) end of the bar, L = 6 in. is the length of the bar, and E=30000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length L of the bar (c) the maximum normal strain in the bar. Answer: (a) 5 = 1 (b) Sa (c) Emax= i x10-6 in. με με
- The normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E where y = 2.1 lb/in.³ is the specific weight of the material, y = 2.0 in. is the distance from the free (i.e., bottom) end of the bar, L = 5 in. is the length of the bar, and E = 27000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length L of the bar (c) the maximum normal strain in the bar. Answer: (a) 8 = i (b) avg (c) Emax = i x10 in. με μεThe normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E where y = 2.9 lb/in.³ is the specific weight of the material, y = 0.5 in. is the distance from the free (i.e., bottom) end of the bar, L = 5 in. is the length of the bar, and E = 25000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length L of the bar. (c) the maximum normal strain in the bar.The normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E where y = 2.0 lb/in.³ is the specific weight of the material, y = 2.8 in. is the distance from the free (i.e., bottom) end of the bar, L = 14 in. is the length of the bar, and E = 20000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length L of the bar (c) the maximum normal strain in the bar. Answer: (a) 8- i (b) Eavg (c) Emax = i x10-6 in. με με
- The normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E where y = 2.4 lb/in.³ is the specific weight of the material, y = 1.8 in. is the distance from the free (i.e., bottom) end of the bar, L = 9 in. is the length of the bar, and E= 26000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length L of the bar. (c) the maximum normal strain in the bar. Calculate the change in length of the bar due to its own weight. Answer: x10-6 in.The normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E where y = 2.9 lb/in.³ is the specific weight of the material, y = 0.5 in. is the distance from the free (i.e., bottom) end of the bar, L = 5 in. is the length of the bar, and E = 25000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length L of the bar. (c) the maximum normal strain in the bar. Part 1 * Your answer is incorrect. Calculate the change in length of the bar due to its own weight. Answer: d= i 2.416 eTextbook and Media x10-6 in.The normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E where y = 2.8 lb/in.3 is the specific weight of the material, y = 2.0 in. is the distance from the free (i.e., bottom) end of the bar, L = 20 in. is the length of the bar, and E= 29000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length L of the bar. (c) the maximum normal strain in the bar. Part 1 Your answer is correct. Calculate the change in length of the bar due to its own weight. Answer: 6 = 6.436 eTextbook and Media Part 2 * Your answer is incorrect. Calculate the average normal strain over the length of the bar. Answer: Eavi 3.22 x10-6 in. eTextbook and Media Save for Later με Attempts: 1 of 5 used Attempts: 2 of 5 used Part 3 The parts of this question must be completed in order. This part will be available when you complete the part above. Submit Answer