Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Vinegar?
required to neutralize the acetic acid in each sample of vinegar,
16. Complete the calculations to find the molarity and percentage of acetic acid in vinegar.
Convert the average volume of NaOH required to reach endpoint from mL to L
Average volume of NaOH required to reach endpoint in mL
15. Subtract the initial volume from the final volume to calculate the volume of NaOH
I DATA
269
12.55
TITRATION DATA (REPORT YOUR VOLUMES TO 1/100TH MI
TRIAL 1
TRIAL 2
Initial base buret reading
Final base buret reading
Volume of sodium hydroxide
(NaOH) required to reach
endpoint in mL
Volume of vinegar used
O15
12.55
TRIAL 3
12:55
24.11
EXTRA TRIAL
24.11
35.39
11.78
12.05
11.56
15.00 mL
15.00 mL
15.00 mL
15.00 mL
(Show calculations here.)
12.05711-56+1178
-27.54
27.54ML
(Show calculations here.)
a7.54ML X IL
0-02754L
:0.02754L
nd bon
1600
Molarity of NAOH (recorded from the standard solution bottle)
0.1
I CALCULATIONS FOR MOLARITY OF ACETIC ACID IN VINEGAR
1. Using the known molarity of NaOH(aq) and the average volume of NaOH(aq) in liters O1=
required to reach the endpoint, calculate the moles of NaOH used in the titration. Show
your calculations using dimensional analysis or the following equation:
moles of NAOH CỢ.Ô2754L X 0. /
M =
Liters of solution
6-002754
2. Since the acid/base mole ratio is 1:1 for this neutralization reaction, how many moles of
acetic acid (HC,H;O,) are present in a 15.00 mL sample of diluted vinegar?
0.002754
moles of NaOH used to reach endpoint of titration
moles of HC,H,02 in diluted vinegar sample
K-11
Nowimuc
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Transcribed Image Text:Vinegar? required to neutralize the acetic acid in each sample of vinegar, 16. Complete the calculations to find the molarity and percentage of acetic acid in vinegar. Convert the average volume of NaOH required to reach endpoint from mL to L Average volume of NaOH required to reach endpoint in mL 15. Subtract the initial volume from the final volume to calculate the volume of NaOH I DATA 269 12.55 TITRATION DATA (REPORT YOUR VOLUMES TO 1/100TH MI TRIAL 1 TRIAL 2 Initial base buret reading Final base buret reading Volume of sodium hydroxide (NaOH) required to reach endpoint in mL Volume of vinegar used O15 12.55 TRIAL 3 12:55 24.11 EXTRA TRIAL 24.11 35.39 11.78 12.05 11.56 15.00 mL 15.00 mL 15.00 mL 15.00 mL (Show calculations here.) 12.05711-56+1178 -27.54 27.54ML (Show calculations here.) a7.54ML X IL 0-02754L :0.02754L nd bon 1600 Molarity of NAOH (recorded from the standard solution bottle) 0.1 I CALCULATIONS FOR MOLARITY OF ACETIC ACID IN VINEGAR 1. Using the known molarity of NaOH(aq) and the average volume of NaOH(aq) in liters O1= required to reach the endpoint, calculate the moles of NaOH used in the titration. Show your calculations using dimensional analysis or the following equation: moles of NAOH CỢ.Ô2754L X 0. / M = Liters of solution 6-002754 2. Since the acid/base mole ratio is 1:1 for this neutralization reaction, how many moles of acetic acid (HC,H;O,) are present in a 15.00 mL sample of diluted vinegar? 0.002754 moles of NaOH used to reach endpoint of titration moles of HC,H,02 in diluted vinegar sample K-11 Nowimuc
MENT K Acid-Base Titration: How Much Acid Is In Vinegar?
B. Calculate the molarity of acetic acid in the diluted vinegar sample using the calculated
moles of HC2H;O2 in the 15.00 mL diluted vinegar sample. Remember to find molarity
the volume must be in liters. (Show work below)
M of HC,H,O, in diluted vinegar sample
4. Give the molarity of acetic acid in the vinegar before it was diluted. The original vinegar
from the store is 10 times more concentrated than the diluted vinegar sample used in
the titration.
O-02754M of HC,H,O, in undiluted or original vinegar
CALCULATIONS FOR MASS PERCENT OF ACETIC ACID IN VINEGAR
5. Convert the moles of acetic acid (HC,H,0,) in the diluted vinegar sample (previously
calculated in question 2) to grams of HC,H,O,. Show your work. (You will need to use
the molar mass of acetic acid for this calculation.)
g of HC,H;O2
5. Using the equation below, calculate the mass percent of acetic acid in the diluted
vinegar sample. The density of the vinegar is 1.00 g/mL so you can assume that the
mass of vinegar in grams is essentially equal to the volume of vinegar in mL. Show
your work below.
mass of acetic acid
x 100
Percent by mass =
mass of vinegar sample
% by mass of HC,H;O, in diluted vinegar sample
7. Give the percent by mass of acetic acid in the vinegar before it was diluted. The original
vinegar from the store is 10 times more concentrated than the diluted vinegar sample
used in the titration.
% by mass of HC,H;O, in undiluted or original vinegar
expand button
Transcribed Image Text:MENT K Acid-Base Titration: How Much Acid Is In Vinegar? B. Calculate the molarity of acetic acid in the diluted vinegar sample using the calculated moles of HC2H;O2 in the 15.00 mL diluted vinegar sample. Remember to find molarity the volume must be in liters. (Show work below) M of HC,H,O, in diluted vinegar sample 4. Give the molarity of acetic acid in the vinegar before it was diluted. The original vinegar from the store is 10 times more concentrated than the diluted vinegar sample used in the titration. O-02754M of HC,H,O, in undiluted or original vinegar CALCULATIONS FOR MASS PERCENT OF ACETIC ACID IN VINEGAR 5. Convert the moles of acetic acid (HC,H,0,) in the diluted vinegar sample (previously calculated in question 2) to grams of HC,H,O,. Show your work. (You will need to use the molar mass of acetic acid for this calculation.) g of HC,H;O2 5. Using the equation below, calculate the mass percent of acetic acid in the diluted vinegar sample. The density of the vinegar is 1.00 g/mL so you can assume that the mass of vinegar in grams is essentially equal to the volume of vinegar in mL. Show your work below. mass of acetic acid x 100 Percent by mass = mass of vinegar sample % by mass of HC,H;O, in diluted vinegar sample 7. Give the percent by mass of acetic acid in the vinegar before it was diluted. The original vinegar from the store is 10 times more concentrated than the diluted vinegar sample used in the titration. % by mass of HC,H;O, in undiluted or original vinegar
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