Use the molarity you calculated for the vinegar solution (the answers here use the molarity with 1 SF) to determine how much vinegar is required to fully react with the two tablets of alkaseltzer, which contain 1916 mg of NaHCO3 each. MM NaHCO3 = 84.007 g/mol. We need with both tablets. The number of moles of CO2 gas produced from this reaction would be → mL of 5% vinegar solution needed to completely react If the CO₂ gas produced had a pressure of 1.00 atm, the temperature was 20°C, and we use R = 0.08206 L atm/mol K, then the volume of this CO2 gas produced from the reaction would be L CO₂.

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Molar mass of acidic acid is 60.052 g/mol

Molarity of acidic acid is .8 M

CH3COOH(aq) + NaHCO3(s) -->
NaCH3COO(aq) + H₂O(1) + CO2(g)
Transcribed Image Text:CH3COOH(aq) + NaHCO3(s) --> NaCH3COO(aq) + H₂O(1) + CO2(g)
Use the molarity you calculated for the vinegar solution (the answers here use
the molarity with 1 SF) to determine how much vinegar is required to fully react
with the two tablets of alkaseltzer, which contain 1916 mg of NaHCO3 each.
MM NaHCO3 = 84.007 g/mol.
We need
→ mL of 5% vinegar solution needed to completely react
with both tablets.
The number of moles of CO2 gas produced from this reaction would be
If the CO₂ gas produced had a pressure of 1.00 atm, the temperature was
20°C, and we use R = 0.08206 L atm/mol K, then the volume of this CO2 gas
produced from the reaction would be
◆L CO₂.
Transcribed Image Text:Use the molarity you calculated for the vinegar solution (the answers here use the molarity with 1 SF) to determine how much vinegar is required to fully react with the two tablets of alkaseltzer, which contain 1916 mg of NaHCO3 each. MM NaHCO3 = 84.007 g/mol. We need → mL of 5% vinegar solution needed to completely react with both tablets. The number of moles of CO2 gas produced from this reaction would be If the CO₂ gas produced had a pressure of 1.00 atm, the temperature was 20°C, and we use R = 0.08206 L atm/mol K, then the volume of this CO2 gas produced from the reaction would be ◆L CO₂.
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