372-8-18-8-132.906Cs➡18-8-1 2-2-8Sya192-8-885.46785R+1 (22LChemistry - 2011 EditionA88-18-32-183. (Balance this reaction In Basic Solution):103¯¯ (aq) + Zn (s) →-1=15-2×3=6Ge(Zn (s)0-11-66 + 6H² + 103 (14) I (4) + 3H₂O→ Zn (uu)2+ÖSUB at theZn²+ (aq) + I (aq)+ 2e-¯)x32+32n (s) 32 (aq) + be68² + 6H²+I03 (64) + 32M(5) → I (aq) + 3H₂O +3² (aa) +6e-60H²+I03(aq) +3Zn(s) → I (14) + 3H₂0 + 3 Zn ((4)сии)2+کی کارا-1 20.180102-839.948Ar024522+2Ne4.0026018180He

Answered: 3. (Balance this reaction In Basic…

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3. (Balance this reaction In Basic Solution): 103 (aq) + Zn (s) → -1=15-2×3=-6 Zn²+ (aq) + (aq)

Chemistry for Engineering Students

4th Edition

ISBN:9781337398909

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter12: Chemical Equilibrium

Section: Chapter Questions

Problem 12.67PAE: 12.67 Hydrofluoric acid is a weak acid used in the building industry to etch patterns into glass for...

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Concept explainers

Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.

Question

37
2-8-18-8-1
32.906
Cs
➡
18-8-1 2-
2-8
Sy
a
19
2-8-8
85.4678
5R
+1 (22L
Chemistry - 2011 Edition
A
88
-18-32-18
3. (Balance this reaction In Basic Solution):
103¯¯ (aq) + Zn (s) →
-1=15-2×3=6
Ge
(Zn (s)
0
-1
1
-66 + 6H² + 103 (14) I (4) + 3H₂O
→ Zn (uu)
2+
Ö
SUB at the
Zn²+ (aq) + I (aq)
+ 2e-¯)x3
2+
32n (s) 32 (aq) + be
68² + 6H²+I03 (64) + 32M(5) → I (aq) + 3H₂O +3² (aa) +6e-
60H²+I03(aq) +3Zn(s) → I (14) + 3H₂0 + 3 Zn ((4)
сии)
2+
کی کارا
-1 20.180
10
2-8
39.948
Ar
0245
22
+2
Ne
4.00260
18
18
0
He

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