3. A molecule absorbs IR at a wavenumber of 1720 cm-1. Which functional group could account for this absorption. I. aldehydes II. esters III. ethers O 1& II 1 & III II ONLY III ONLY
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- 6. (Chapter 15 - 47b) An aromatic compound, C9H12 has the following H NMR spectrum and a peak at 750 cmt in its IR spectrum. Answer the following questions. Chem. shift Rel. area 1.19 2.31 2.64 7.13 1.50 1.50 1.00 2.00 TMS 10 3 O ppm Chemical shift (6) 4(a). The IR peak at 750 cm in its IR spectrum indicate that the compound is. disubstituted = 4(b) The name of the compound is = Intensity-Which molecule is labelled with the correct E and Z descriptors? E A O. E Z O. C D E.L. ca tramolecular D-A 2. then retro-D-A (loss Co,) 4. CO, Me cntremolecular かA 5. intramaka cular NO 3+2] N-OH NaOcl 6. entramalecular [312) CN 7. CN
- 3) Give the mechanism B. XOH 애 C. [ D. 1.) Not 2.) Br xs HI 4 E. 2SH NOCH, R5₂ 1₂0III Jdve this response. estion 13 8. Determine the priority of the groups and hence the absolution configuration of the stereocentre in this co Br vThe highest priority group is A. Br v The second highest priority group is B.COCH3 C.S v The configuration is D.C6H5 E. R will save this response.Attempt to explain the main features of the H NMR spectrum of crotonic acid (4), Spec. 4. Deduce the stereochemistry of the carboxylic acid (CO₂H peak not shown). S ... 8 0 SPEC CHCHỊCH CÔ, H 4
- -R -R N- H-B: H-B R R NCCD3 + CH2CI2 N. CICH2CI CD;CN CH3 CH3 R. A B A similar iridium complex was studied. It was found that the reaction with a Tp ligand where R = Me occurred with a very high rate (tsp< 5 s at0 °C), while the unsubstituted Tp complex had a much slower ligand substitution rate (tap = 75 min at room temp). Based on this result, does this complex undergo ligand substitution by the same mechanism as the ruthenium complex, or by another mechanism. Explain.What is the standard solvent in both 1H and 13C NMR? A. (CH3)4Si B. D2O C. CDCl3 D. C6H6 E. none of the aboveWhat compound does this NMR show evidence for? Integration values are given in red below the peaks. 23 4 22 PPM O a. o b. olaa od. ое.
- Associative interchange mechanism is encountered in O a. early transition states. а. O b. actinoids c. lanthanoids O d. late transition statesp-nitroaniline (2max : 375 nm) absorbs at a longer than Phitrobenzene (c) Explain why wavelength (hmax : 260 nm). (ij Write a short note on absorption. spectra complexes of charge transferCHEM 241L. Exp#12 NMR Spectre 3. Compound 3 is a low boiling liquid (bp-58°C) that reacts with Br. in CCl. to form a 1,1,2,2 tetra-bromide. Elemental Analysis: C-48.36%, II - 4.06%; contains halogen "C Spectral Data: 80.4ppm (doublet), 68.3ppm (singlet), 34.7ppm (triplet) Mass Spectrom Absorbence Intonally 48 'H NMR Infrared Spectrom 4000 3000 2500 2000 74 70 80 90 100 110 120 130 140 150 160 170 100 mie Wave Number, cm .1 1300 1200 1100 1000 mon 1600 Wavelength, microne Compound 3 Structure Ppin
