IF NEEEDEDShow complete solution, including the process of integration, solving for the area/moment of the area via integration, evaluation of the definite integral and algebraic/trigonometric manipulation.Draw complete FBD with complete labels thank you in advance *^_^* A2.25 m-4 m-e=90° µ=0.13m3 mk= 200 N /mF(x) =Nxur_° + xu°3 mboundary from x =1 to x = 2-2m-F1 m-3 m3 m3 m-F(x) =Inxboundary from x =1 to x = 23 m3 mWhat is the force in member CE if there is a 25 Newton horizontal force going away from Gand the left rope of pulley A has the higher tension?B

Fx=e-lnxelnx+e-lnx+lncos-11-sin2xx N/cm

3 m B -3 m- -3 m- C 2.25 m k = 200 N/m- -3 m D E 4 m F 3 m 3 m 3 m 3 m A -0-90° p=0.1 -2m-1m- F(x)= -Inx Inx+-Inx F(x)= -Inx -Inx boundary from x=1 to x = 2 + boundary from x=1 to x = 2 In(cos~¹((√1- (sin(x))²))) In(cos-¹((√1- (sin(x))²))) N cm X cm What is the force in member CE if there is a 25 Newton horizontal force going away from G and the left rope of pulley A has the higher tension?

3 m B -3 m- -3 m- C 2.25 m k = 200 N/m- -3 m D E 4 m F 3 m 3 m 3 m 3 m A -0-90° p=0.1 -2m-1m- F(x)= -Inx Inx+-Inx F(x)= -Inx -Inx boundary from x=1 to x = 2 + boundary from x=1 to x = 2 In(cos~¹((√1- (sin(x))²))) In(cos-¹((√1- (sin(x))²))) N cm X cm What is the force in member CE if there is a 25 Newton horizontal force going away from G and the left rope of pulley A has the higher tension?

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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