Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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- In peas, round (R) is dominant to wrinkled. (r )You cross a round pea plant to a wrinkled pea plant and half the offspring are round and half the offspring are wrinkled. What are the genotypes of the parents?arrow_forwardGiven these parents-note, they are NOT quite the same as each other!: mom = Aa Bb Cc Dd dad = Aa Bb cc Dd NOTE that the A gene acts incompletely dominantly. a) What chance does their baby having the "strongest phenotype" in A, being recessive in b, recessive in c, and dominant in D? Give one fraction. Show work. b) phenotype? Now assume mom was CC instead of Cc. Now what is the chance of having that samearrow_forwardIn a newly discovered species of Giant Pacific Octopus, long tentacles (L) are dominant to short tentacles (l), strong suction cups (S) are dominant to weak suction cups (s), and brown body color (B) is dominant to red body color (b). A trihybrid test cross was performed between male octopuses that were heterozygous for all three genes, and female octopuses that were homozygous recessive. (You may assume that the dominant alleles exhibit complete dominance.) The results of this cross are shown in the table attached Please complete the table and answer the following questions: a) Are these genes linked? Explain why you think these genes are linked or unlinked? b) What is the genotype of each of the two parents that produced the offspring shown in the data table? Please indicate the linkage phase as you write the genotype of each parent. (Please write the genotypes in the format: xyz/xyz.) Genotype of male parent octopus: Genotype of female parent octopus:arrow_forward
- 1) Perception of a bitter taste from phenylthiocarbamide (PTC) is dominant (T) to not being able to taste PTC. Albinism is recessive to normal pigmentation (A). The genes controlling these traits are on separate chromosomes. a. A normally pigmented woman who cannot taste PTC has a father who is an albino taster, marries a many homozygous for normal pigmentation who is a PTC taster, but whose mother did not taste PTC. What are the genotypes of the woman and man listed here? b. Assuming the man and woman in the above section have children, what percentage of these children will be albino? c. What percentage of these children will have the same phenotype as their mother?arrow_forwardLabrador retrievers are commonly black, brown, or yellow. Two different genes determine coat color in Labrador retrievers. The B gene determines pigment color (B is black, bb is brown). The E gene determines whether the pigment can be deposited in the hair shaft: ee prevents any pigment from being deposited, resulting in yellow dogs. You want to breed Labrador retrievers, and you cross a true-breeding brown Labrador retriever to a true-breeding yellow Labrador retriever. All 15 of the F1 puppies are black. After the puppies grow up, you cross two of the F1 black dogs together. In the F2 generation you get 8 black puppies, 4 yellow puppies, and 3 brown puppies. Question 1 Part 1 What is/are the possible genotype(s) of the true-breeding brown lab in the P generation? bbee bbee Could be either answer bbEE or bbEe Could be either answer bbEE or bbEe bbEE bbEE bbEe bbEe Brown Brown Question 2 Part 2 What is/are the possible…arrow_forwardStep by steparrow_forward
- Let's continue with these two genes that control the color and texture of tomatoes. Allele "R" generates a red coloration, and is dominant. Allele "r" generates a green coloration and is recessive. Allele "S" generates a smooth texture, and is dominant. Allele "s" generates a rough texture and is recessive. You now decide to cross your dihybrid RrSs but this one with a tomato with Rrss. RrSs x Rrss What is the probability of getting Red tomatoes with Rough texture in this new cross? Assume complete dominance and 100% penetrance and expressivity. 9/16 3/8 1/4 1/16 3/16 1/8 x 1/2arrow_forwardThe rare recessive trait of albinism manifests as a lack of pigmentation in the skin. Albinism can be caused by mutations in any of several genes. A female mouse named Blanca exhibits albinism. She mated with two male mice, Ash and Whitey, and produced 3 offspring from each mating. • Ash exhibited albinism; all 3 of Blanca and Ash's offspring showed albinism. Whitey exhibited albinism; none of Blanca and Whitey's offspring showed albinism ● Determine the genotype for the offspring of Blanca and Ash. Capital letters denote wildtype alleles, and lower case letters denote mutant alleles. Mice are diploid. aaBB If Blanca and Ash had a fourth mouse in their litter, what is the probability that the fourth mouse will exhibit albinism? 1.0 Determine the most likely genotype for the offspring of Blanca and Whitey. Capital letters denote wildtype alleles, and lower case letters denote mutant alleles. Mice are diploid. AaBb If Blanca and Whitey had a fourth mouse in their litter, what is the…arrow_forwardIn Labrador dogs, coat color is controlled by the genotypes of two genes. In one gene, the dominant allele, B, produces black fur, and the recessive allele, b, produces brown fur. However, if a second gene possesses two recessive alleles, ee, the dog produces yellow fur, regardless of the genotype of the first gene. If two dogs that are heterozygous for both genes, BbEe mated, what would be the frequency of the three phenotypes, black, brown, and yellow?arrow_forward
- In humans, there is a gene that influences the ability to smell the thioesters present in urine after asparagus is eaten. The ability to smell these compounds is an autosomal dominant trait. A is dominant and confers the ability to smell these thioesters a is recessive and does NOT confer the ability to smell these thioesters p = freq (A) = frequency of allele A in the population = number of A alleles/ total number of alleles %3D q = freq (a) = frequency of allele a in the population where p + q = 1 and, therefore, p? + 2pq + q? = 1 and %3D %D p? = freq (AA) = frequency of genotype AA = number of AA individuals/ total number of individuals %3D 2pq = freq (Aa) = frequency of genotype Aa q? = freq (aa) = frequency of genotype aa Phenotype Number of People Able to smell thioesters 378 Unable to smell thioesters 1323 Total 1701 1. Calculate p and q for this population. 2. Calculate p?, 2pq, and q? for this population.arrow_forwardThe bison herd on Konza Prairie has begun to show a genetic defect. Some of the males have a condition known as "rabbit hock" in which the knee of the back leg is malformed slightly. This condition is controlled by a sex-linked gene and it is recessive. Now, suppose that the herd bull (the dominant one which does most of the breeding) who is normal (XN) mates with a cow that is a carrier for rabbit hock. What are his chances of producing a normal son (bull)? If he mates with this cow every year, what percentage of their daughters will have normal knees? What percentage of their daughters will be carriers of rabbit hock?arrow_forwardIn mice, the presence of a dominant A allele results in the agouti pattern of fur color, whereas the aa homozygous recessive results in a solid color pattern. The presence of another dominant B allele results in black fur color, whereas the homozygous recessive bb results in brown fur color. The presence of a third dominant C allele is required for any color to be observed (brown or black), whereas the homozygous recessive cc results in lack of any color whatsoever (albino). What is the phenotype of a mouse with the following genotype? Aa bb cc albino Agouti color pattern and brown Solid color pattern and brown Agouti color pattern and black Solid color pattern and blackarrow_forward
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