3) Estimating the Difference Between Two Means: Unknown Variance (Assumed Unequal) a) A car manufacturer outsources production of a certain automotive component. The company has found a cheaper supplier (supplier 2), but wants to make sure that the component is of the same quality. The standard deviations in component lifetimes are unknown. 12 components from each supplier are tested and the average lifetime for the new supplier's component is 1,500 miles shorter compared to the original supplier's component (that is, X₁ X₂ = 1,500). The standard deviations for the two samples are S₁ = 1,250 and S₂ = 1,100 miles. Find a 96% confidence interval on the difference in average lifetime between the two populations (μ₁ −μ₂).

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
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ISBN:9780079039897
Author:Carter
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Chapter10: Statistics
Section10.3: Measures Of Spread
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3) Estimating the Difference Between Two Means: Unknown Variance (Assumed Unequal)
a) A car manufacturer outsources production of a certain automotive component. The company
has found a cheaper supplier (supplier 2), but wants to make sure that the component is of
the same quality. The standard deviations in component lifetimes are unknown.
12 components from each supplier are tested and the average lifetime for the new supplier's
component is 1,500 miles shorter compared to the original supplier's component (that is,
X₁ X₂ = 1,500). The standard deviations for the two samples are S₁ = 1,250 and S₂ =
1,100 miles. Find a 96% confidence interval on the difference in average lifetime between
the two populations (₁-₂).
.<μ<.
Transcribed Image Text:3) Estimating the Difference Between Two Means: Unknown Variance (Assumed Unequal) a) A car manufacturer outsources production of a certain automotive component. The company has found a cheaper supplier (supplier 2), but wants to make sure that the component is of the same quality. The standard deviations in component lifetimes are unknown. 12 components from each supplier are tested and the average lifetime for the new supplier's component is 1,500 miles shorter compared to the original supplier's component (that is, X₁ X₂ = 1,500). The standard deviations for the two samples are S₁ = 1,250 and S₂ = 1,100 miles. Find a 96% confidence interval on the difference in average lifetime between the two populations (₁-₂). .<μ<.
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