2p.y = 2a =760.4+3.42나0.2 +0.85Open circuit tests carried out on a 3.5 MVA, 4.16 kV, 60Hz, three phase star connected synchronous generatorgave the following results:EPM: Vpnt Ip.y (2p.u)► If (A):10▸ Ę₁ (KV):153.5 4.16 5.72025306.257.95=1+120° 6.2 +10.81+1 (0.87 176.1 +0.87 £76.7➤ In the short circuit test a field current of 20A was neededto circulate full load current. The armature winding 1+0.2+10resistance is 1.20 /phase, the field winding resistance is500 and the rotational loss is 250kW. Determine thepower angle, the voltage regulation and the efficiencywhen the generator delivers rated load at terminal voltageof 4.4 kV and at 0.8 power factor leading.▸ Draw the power flow diagram for the generator andinclude all values of power flows.1.2 + JoE =14743

Answered: Image /qna-images/answer/77b84624-5ebc-4634-8220-e11e4d5c7784.jpg

Answered: 2p.y = 2a = 76 0.4+3.42 나 0.2 +0.85…

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter11: Transient Stability

Section: Chapter Questions

Problem 11.19P

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urgent required.
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