2/59 At time t = 10 s, the velocity of a particle moving in the x-y plane is v= 0.1i + 2j m/s. By time = 10.1 s, its velocity has become -0.1i + 1.8j m/s. Determine the magnitude aay of its average acceleration during this interval and the angle made by the average accel- eration with the positive x-axis.

The velocity of a particle moving in the x-y plane is given by (5.72i + 7.27j) m/s at time t = 5.22 s. Its average acceleration during the next 0.019 s is (3.1i + 8.0j) m/s2. Determine the velocity v of the particle at t = 5.239 s and the angle e between the average- acceleration vector and the velocity vector at t = 5.239 s. Answers: i i+ i j) m/s i

The y-coordinate of a particle in curvilinear motion is given by y = 8.3t3 - 5.4t, where y is in inches andt is in seconds. Also, the particle has an acceleration in the x-direction given by ax = 10.6t in./sec?. If the velocity of the particle in the x-direction is 13.0 in./sec when t = 0, calculate the magnitudes of the velocity v and acceleration a of the particle when t = 1.7 sec. Construct v and a in your solution. %3D Answers: When t = 1.7 sec, V = i in./sec a = in./sec2

Your answer is partially correct. The velocity of a particle moving in the x-y plane is given by (7.70i + 4.91j) m/s at time t = 7.38 s. Its average acceleration during the next 0.029 s is (3.3i + 2.6j) m/s?. Determine the velocity v of the particle at t = 7.409 s and the angle 8 between the average- acceleration vector and the velocity vector at t = 7.409 s. Answers: v = ( 7.7957 i+ 4.9754 j) m/s 5.73