= 240020° + 4. 1672 - 36. 86° (6 +j30) = 240020° +4. 1672- 36. 86° x 30.59278. 69° = 2494.97 +j85.005 V₁ = 2496.4121.94° V₁ = 2496.4 V
= 240020° + 4. 1672 - 36. 86° (6 +j30) = 240020° +4. 1672- 36. 86° x 30.59278. 69° = 2494.97 +j85.005 V₁ = 2496.4121.94° V₁ = 2496.4 V
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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The problem is to find the primary voltage required, but I already got a solution. The points is in this part (picture below), I don't know how solve involving the angular like (-36.86°). Can you explain how to solve involving an angle?
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