24/0° V Magnitude of ₁ = 1₁ Magnitude of 1₂ = 2Ω j2 Ω Find the magnitude of the labeled currents 1₁ and 12 and the average power in the voltage source and the 4 2 resistor according to the passive sign convention. This does have a mutual inductance component. Give your answers two one decimal (such as 6.5 or -15.2). Average power in voltage source P = j2 Average power in 4 2 resistor = A 1₂ A j4 S2₂ W 4Ω W

Electricity for Refrigeration, Heating, and Air Conditioning (MindTap Course List)
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Chapter7: Alternating Current, Power Distribution, And Voltage Systems
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24/0° V(+
Magnitude of 1₁
=
2Ω
Magnitude of 12 =
j2 Ω
Find the magnitude of the labeled currents 1₁ and 12 and the average power in the voltage source and
the 4 resistor according to the passive sign convention. This does have a mutual inductance
component. Give your answers two one decimal (such as 6.5 or -15.2).
Average power in voltage source P =
j2
Average power in 4 Q2 resistor =
A
1₂
A
j4Q
W
Σ4Ω
W
Transcribed Image Text:24/0° V(+ Magnitude of 1₁ = 2Ω Magnitude of 12 = j2 Ω Find the magnitude of the labeled currents 1₁ and 12 and the average power in the voltage source and the 4 resistor according to the passive sign convention. This does have a mutual inductance component. Give your answers two one decimal (such as 6.5 or -15.2). Average power in voltage source P = j2 Average power in 4 Q2 resistor = A 1₂ A j4Q W Σ4Ω W
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