21-B // A steel bar has a square section of 10 mm side and a length of 60 mm, subjected to a tension force of 50 KN, as a result the bar has extended 2 mm; Calculate: 1-Yong modulus 2- The engineering stress 3- The engineering se stein 4- The true stress 5- The true strain
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- The figure shows a rigid bar that is supported by a pin at A and two rods, one made of steel and the other of bronze. Neglecting the weight of the bar, compute the force (in N) in the steel rod caused by the 42758-Nload, using the following data: length of steel = 1.27 m, length of bronze = 2.06 m Area of steel = 522 mm, Area of bronze = 239 mm Modulus of elasticity of steel = 216 Gpa, Modulus of elasticity of bronze = 84 Gpa x= 0.69 m, y = 1.08 m, and z = 0.86 m. Round off the final answer to three decimal places. ... Bronze Steel Ey te zThe figure shows a rigid bar that is supported by a pin at A and two rods, one made of steel and the other of bronze. Neglecting the weight of the bar, compute the force (in N) in the bronze rod caused by the 42563-Nload, using the following data: length of steel = 1.56 m, length of bronze = 2.18 m Area of steel = 563 mm, Area of bronze = 233 mm Modulus of elasticity of steel = 193 Gpa, Modulus of elasticity of bronze = 82 Gpa x = 0.69 m, y = 1.03 m, and z = 0.79 m.The figure shows a rigid bar that is supported by a pin at A and two rods, one made of steel and the other of bronze. Neglecting the weight of the bar, compute the force (in N) in the bronze rod caused by the 45846-Nload, using the following data: length of steel = 11 m, length of bronze = 2.3 m Area of steel = 562 mm, Area of bronze = 335 mm Modulus of elasticity of steel = 195 Gpa, Modulus of elasticity of bronze = 80 Gpa x= 0.55 m, y = 1.12 m, and z = 0.78 m. Round off the final answer to two decimal places. ... Bronze Steel
- The figure shows a rigid bar that is supported by a pin at A and two rods, one made of steel and the other of bronze. Neglecting the weight of the bar, compute the force (in N) in the bronze rod caused by the 48512-Nload, using the following data: length of steel = 1.42 m, length of bronze = 2.36 m Area of steel = 639 mm, Area of bronze = 319 mm Modulus of elasticity of steel = 180 Gpa, Modulus of elasticity of bronze = 81 Gpa x = 0.58 m, y = 1.13 m, and z = 0.72 m. Round off the final answer to two decimal places.The figure shows a rigid bar that is supported by a pin at A and two rods, one made of steel and the other of bronze. Neglecting the weight of the bar, compute the force (in N) in the steel rod caused by the 43091-Nload, using the following data: length of steel = 1.36 m, length of bronze = 2.08 m Area of steel = 562 mm, Area of bronze = 243 mm Modulus of elasticity of steel = 215 Gpa, Modulus of elasticity of bronze = 102 Gpa x = 0.63 m, y = 1.01 m, and z = 0.84 m.A round steel bar with a diameter of 1.500 in is subjected to the axial loads shown. P1 = 95 k, P2 = 115 k, P3= 55 k, P4 = (P1-P2+P3) k. If Section 2 has a length, L2 = 65 inches, find the change in length of Section 2. Report the answer below in inches, absolute value, 3 significant digits. P1 Your Answer: 100 inches Round Steel Bar P2 Section 2 12 P3 80 inches P4
- ENTER YOUR ANSWER THE WAY I SPECIFY HERE IN ADDITION TO DOING IT ON SCRATCH PAPER 400 N 800 N B D A E C 2 m Use the method of sections to calculate the axial force in members AC and BC. Enter your answer in the following way rounded to the nearest whole number. Example If your answer is TAC 2 N tension TBC =3.1 N compression. enter 2Tension;3Compression Enter TAC then TBC (no space)Q1: 30-mm-diameter steel bar is to be used as a torsion spring. If the torsional stress in the bar is not to exceed 110 MPa when one end is twisted through an angle of 30°, what must be the length of the bar in m? modulus of rigidity=80 GPa . (close to two decimal)Q1: A steel pipe column with outside diameter 0.5 in and its wall thickness 0,25 in. supports a load of 4.45 kN. The steel pipe rests on a square steel base plate, this base plate is resting on a concrete slab as illustrated in the attached figure. 1-Determine the bearing stress between the stcel pipe and the stecl plate. 2-If the bearing stress of the steel plate on the concrete slab must be limited to 90 nci what is the minimum allowable plate dimension (a)? 3-Determine the average shear stress in the steel plate, explain? Load Outside diameter - 6.5S in. Wall thickness - 0.25 in. Square steel- base plate Concrete slab
- Compound axial member ABC has a uniform diameter of d-2.4 in. Segment (1) is an aluminum [E₁ - 10,000 ksi] alloy and segment (2) is a copper [E₂ - 17,000 ksi] alloy. The lengths of segments (1) and (2) are L₁ - 78 in. and L₂ - 150 in., respectively. Determine the force P required to stretch compound member ABC by a total of 0.35 in. L₁ A Part 1 Aluminum Answer: A- B Save for Later Calculate the cross-sectional area of the compound member. L2 (2) Copper in.² C P Attempts: 0 of 1 used Submit Answer Part 2 The parts of this question must be completed in order. This part will be available when you complete the part above. Part 3 The parts of this question must be completed in order. This part will be available when you complete the part above.Q1: An Iron bar has a length of 50 m when the temperature is (-20 "C) .what is the length of the bar in a summer day when the temperature is (38 C) ?Calculate the thermal stress set up in the bar on summer day.a=12 x10 C ,E=25x10 Pa.Q1- The rigid bar of negligible weight is supported as shown in Fig- IS W- 80 kN, compute the temperature change of the assembly that will cause a tensile stress of 50 MPa in the steel rod. Use the following data: Bre Steel 15 m A (mm') a (/c°) 110m E (GPa) Steel rod 300 Bronze rod 1400 11.7* 10* 200 18.9 10 25m 83