- 2.5 m- 2.5 m B -3 m 450 kg 5 m

The 2000 kg concrete pipe has a center of mass at point G. If it is suspended from cables AB and AC. The diameters of AB and AC are 12 mm and 10 mm, respectively. Determine the weight of the concrete pipe ( in N).

4. Wet concrete exerts a pressure distribution along the wall of the form. Determine the resultant force of this distribution and specify the height h where the bracing strut should be placed so that it lies through the line of action of the resultant force. The wall has a width of 5 m. Cp = (4z) kPa

The plant in the picture has mass of 29 kg, and is hanging at a distance of 1.4 meters from the wall. The horizontal rod has mass of 6.2 kg. Assume that its weight is evenly distributed, therefore it can be treated as a single force at the center of mass. The rod is 2 meters long, and there is a cable at a 23° angle supporting it at the end. Center of mass of rod from the point = 2/2=1m Using the wall as the axis of rotation, find the magnitude of the downward torque, from both the weight of the rod and the weight of the plant. t=458.64Nm a.The downward torque is balanced by the upward torque from the force of tension. Find the magnitude of the force of tension. T=?N b.F is the contact force between the rod and the wall. Using the other horizontal force in the problem, find the horizontal component of F (the normal force) that must be present for the rod to be at equilibrium. Fx=?N c.There is a vertical force from a component of the tension, but this is not enough to balance the…