2.29. A cylindrical steel shaft is required to transmit a bending moment of 1000 Nm and a torque of 2200 Nm with a safety factor against yielding of 3. If the steel has a yield stress of 250 MPa, find the minimum permissible diameter for the shaft. Use von Mises' theory of yielding.
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- A stepped shaft ABC consisting of two solid, circular segments is subjected to torques T}and T2acting in opposite directions, as shown in the figure. The larger segment of the shaft has a diameter of dv- 2.25 in. and a length Lt= 30 in.; the smaller segment has a diameter d2— 1.75 in. and a length L, = 20 in. The torques are T, = 21,000 lb-in. and fz=10.000 lb-in. (a) Find reaction torque TAat support A. (b) Find the internal torque T(x) at two locations: x = L1/2 and x = L1+ L2/2. Show these internal torques on properly drawn free-body diagrams (FBDs).3.9 A square steel rod 20 mm on a side develops a tor- sional shear stress of 50 MPa when subjected to torque. Calculate the torque and the angle of twist over a length of 1.8 m. G = 80 GPa.A mild steel shaft of 60 mm diameter is subjected to a bending moment of 2200 Nm and a torque T. If the yield point of the steel in tension is 200 MPa, find the maximum value of this torque without causing yielding of the shaft according to:1. The maximum principal stress theory;2. The maximum shear stress theory; and3. The maximum distortion strain energy theory of yielding
- A cylindrical steel shaft is required to transmit a bending moment of 1000 Nm and a torque of 2200 Nm with a safety factor against yielding of 3. If the steel has a yield stress of 250 MPa, find the minimum permissible diameter for the shaft. Use von Mises’ theory of yielding.1. A solid circular shaft transmits 75 kW power at 200 rpm. Calculate the diameter of the shaft and the maximum shear stress acting on it, if the twist in the shaft is not exceeding 1° in 2 m length of the shaft. Take modulus of rigidity as 102 GPa.A hollow steel shaft is stressed to 55 MPa by a torque of 100,000 ft-lb. If the inside diameter is 2/3 of the outside diameter and if G = 83 GPa, find the angle of twist in degrees if the shaft is 5 meters long.
- 2. Solve the following problem Two designs for a shaft are being considered. Both have an outside diameter of 70 m and are 900 mm long. One is solid but the other is hollow with an internal diameter of 50 mm. Both are made from steel (G=120 GPa). Critically evaluate and compare the torsional shear stress, angle of twist of the two designs if they are subjected to a torque ofT 171N.m the missing Torque 171(T).Ahollow shaft with an external diameter of 150 mm transmits a maximum torque of 13 kNm. The shaft length is 5 m,and the maximum shear stress is limited to 40 MPa. If G = 84 x 103N/mm2, calculate;2.1 the internal diameter of the shaft.2.2 the angle of twist in degrees.2.3 the minimum shear stress in the shaft.A mild steel shaft of 50 mm diameter is subjected to a bending moment of 2000 N-m and a torque T. If the yield point of the steel in tension is 200 MPa, find the maximum value of this torque without causing yielding of the shaft according to The maximum principal stress; The maximum shear stress; and The maximum distortion strain energy theory of yielding
- A solid steel shaft must not twist through more than 3° in a 6-m length whensubjected to a torque of 12 kN • m. (a) Find the diameter of the smallest shaft that can be used. (b) What is the maximum shear stress in the shaft of this diameter? Use G = 83 GPa for steel.A uniform shaft of diameter 30 mm is subject to a 60 N of tangential force. Calculate the shear stress induced in the shaft.Solid circular shaft is under bending and torsion loadings. Uniaxial tensile yield strength of the material is 180 MPa, torque applied is 15 kN.m and bending moment applied is 3 kN.m. Calculate the value of the diameter d of the shaft based on the maximum-shear-stress theory of failure (Tresca criterion).