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The two 10-cmcm-long parallel wires in the figure are separated by 5.0 mmmm. For what value of the resistor R will the force between the two wires be 9.9×10−5 N?
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- 3. R1 = 18 Q A В R2 = 9 Q 12 = 2.5 A VT = 97.5 V R4 = 14 Q R3 = 16 Q R5 = 7 Q R6 Determine: R6 = PT = RT = I| = 14 = 15 = 16 = IT = V2 = V3 = V4 =(a) What is the average power output of a heart defibrillator that dissipates 400 J of energy in 10.0 ms? (b) Considering the high-power output, why doesn’t the defibrillator produce serious bums?Determinea. Ceg, b. qeg. 91, 92, 93 c. V, V2 and V30of the given illustration below. C1 C2 2F 4F 6F V = 10 v.
- Calculate the current through resistor R₁. Give your answer in units of milliamperes. Please enter a numerical answer below. Accepted formats are numbers or "e" based scientific notation e.g. 0.23, -2, 1e6, 5.23e-8 Enter answer here mA51. The switch in Figure P27.5la closes when AV, >AV and opens when AV.What is the value of R3 in the figure? R1 = 14.3Ω, R2 = 18.9Ω, ΔV = 7.00 V, I = 7.80A 0.991Ω 0.897Ω 1.01Ω 0.333ΩA power supply with a DC voltage of 5.0 V discharges 500.0 J of energy through a 25 Ohm resistor. How much total electric charge must flow between the battery's terminals to discharge this much energy? a. 0.05 C b. 0.01 C c. 100 C d. 0.2 C e. 2500 CAt t = 0 the switch S is closed with the capacitor uncharged. If C = 30 mF, ɛ = 30 V, and R = 7.7 kN, what is the potential difference across the capacitor when / = 2.0 mA? R O a. 22.30 V O b. 6.90 V O c. 18.45 V O d. 10.75 V O e. 14.60 VO-8.00 V 20.0 V O O.4.00 V O-16.0 V O -4.00 V 8.00 V -20.0 V O ov 16.0 V 3.00 Ω 1.00 ΩSEE MORE QUESTIONS