d B The two straight wires above are L = 11.5 cm long, and d = 6.00 cm apart have a current of /= 1.45 A flowing in the same direction through each of them. What is the force (magnitude and direction) that wire A exerts on wire B? ○ 5.56×107 N up ○ 8.06×107 N down 5.56×107 N down 8.06×107 N up

Each of the eight conductors in the figure carries 3.15 A of current into or out of the page. Two paths are indicated for the line integral B. ds. What is the value of the integral for (a) path 1 and (b) path 2?

Two long, parallel wires are separated by a distance of 0.400 m (see (Figure 1)). The currents I₁ and I2 have the directions shown. Figure 1₁ = 5.00 A ↑ 0.400 m 1₂ = 2.00 A 1 of 1 Part A Calculate the magnitude of the force exerted by each wire on a 1.20 m length of the other. Express your answer with the appropriate units. F = Submit Part B Part C F = Submit HA Value Request Answer Each current is doubled, so that I₁ becomes 10.0 A and I2 becomes 4.00 A. Now what is the magnitude of the force that each wire exerts on a 1.20 m length of the other? Express your answer with the appropriate units. Provide Feedback UA Value Units Request Answer ? Units ?

Physics students, wanted to investigate the forces of attraction (F) between two parallel conductors carrying currents li and l2 (also known as Ampere's Law) The students noticed that as the length of the parallel conductors (/) was increased the force of attraction between the conductors (F) also increased. The data collected is in the |L= SA conductor 1 average separation (d = 0.50m) table: conductor 2 Length, / (m) Force, F (x 10-5 N) 12= 5A 1.00 9.00 1.20 10.8 1.40 12,5 1.60 14.2 1.80 16.2 (iii) On the grid plot the force and length values from the table. (iv) Draw the line of best fit (v) Find the slope of the line of best fit. (c) Use the slope calculated and the Ampere's Law equation to determine the experimental value of the magnetic force constant, k.

O 180, 90, 180 When using the Biot-Savart law, the angle between 7 and ds is _________ degrees for the left, degrees for the semicircle, and degrees for the right segment of the wire. Use the convention that ds points in the direction of the current. O 180, 90, 0 O 90, 0, 90 O 0.90.0 R O 0, 90, 180 H