2. The average length of time for students to register for fall classes at a certain college has been 50 minutes. A new registration procedure using modern computing machine is being tried. If a random sample of 12 students had an average registration time of 42 minutes with a standard deviation of 11.9 minutes under the new system, test the hypothesis that the population mean is now less than 50, using a level of significance of 0.05. (Assuming Normal Distribution) Но: На: a: Tail: Test Statistic: df: Critical Value/Tabular Value: Area of Rejection and Acceptance:

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter13: Probability And Calculus
Section13.3: Special Probability Density Functions
Problem 10E
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2. The average length of time for students to register for fall classes at a certain college has
been 50 minutes. A new registration procedure using modern computing machine is being
tried. If a random sample of 12 students had an average registration time of 42 minutes with
a standard deviation of 11.9 minutes under the new system, test the hypothesis that the
population mean is now less than 50, using a level of significance of 0.05. (Assuming Normal
Distribution)
Но:
На:
a:
Tail:
Test Statistic:
df:
Critical Value/Tabular Value:
Area of Rejection and Acceptance:
Computations:
Decision:
Analysis:
Transcribed Image Text:2. The average length of time for students to register for fall classes at a certain college has been 50 minutes. A new registration procedure using modern computing machine is being tried. If a random sample of 12 students had an average registration time of 42 minutes with a standard deviation of 11.9 minutes under the new system, test the hypothesis that the population mean is now less than 50, using a level of significance of 0.05. (Assuming Normal Distribution) Но: На: a: Tail: Test Statistic: df: Critical Value/Tabular Value: Area of Rejection and Acceptance: Computations: Decision: Analysis:
II.
Application of the Normal Curve
1. A distribution of test scores followsthe normal distribution with x= 80, s = 12, n= 600. How
many scores would you expectto find below a score of 90?
a. Solution:
b. Area of Z
2. Above of Z= 1.72
a. Solution:
b. Area of Z
Transcribed Image Text:II. Application of the Normal Curve 1. A distribution of test scores followsthe normal distribution with x= 80, s = 12, n= 600. How many scores would you expectto find below a score of 90? a. Solution: b. Area of Z 2. Above of Z= 1.72 a. Solution: b. Area of Z
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