PLEASE COMPLETE STEP 1 TO 5 and DO NOT USE EXCEL. Step 1. State Ha and HoStep 2. Level of significanceStep 3. Test-statistic used (z-test or t-test)Step 4- Compute the test statistic Step 5- conclusion Use the traditional method of hypothesis testing. Complete the step 1-5.1. Theро.can you conclude that the averag2. The Medical Rehabilitation Education Foundation reports that the average cost of rehabilitationfor stroke victims is $24,672. To see if the average cost of rehabilitation is different at aparticular hospital, a researcher selects a random sample of 35 stroke victims at the hospitaland finds that the average cost of their rehabilitation is $26,343. The standard deviation of thepopulation is $3251. At a = 0.01, can it be concluded that the average cost of strokerehabilitation at a particular hospital is different from $24,672?3. The Family and Medical Leave Act provides job protection and unpaid time off from work for aserious illness or birth of a child. In 2000, 60% of the respondents of a survey stated that it wasvery easy to get time off for these circumstances. A researcher wishes to see if the percentagewho said that it was very easy to get time off has changed. A sample of 100 people who usedthe leave said that 53% found it easy to use the leave. At a = 0.01, has the percentagechanged?4. It has been found that 85.6% of all enrolled college and university students in the United Statesare undergraduates. A random sample of 500 enrolled college students in a particular staterevealed that 420 of them were undergraduates. Is there sufficient evidence to conclude thatthe proportion differs from the national percentage? Use a = 0.05.5. A physician claims that joggers' maximal volume oxygen uptake is greater than the average ofall adults. A sample of 15 joggers has a mean of 40.6 milliliters per kilogram (ml/kg) and astandard deviation of 6 ml/kg. If the average of all adults is 36.7 ml/kg, is there enoughevidence to support the physician's claim at a = 0.05?plant foodnew6. The average 1-ounce chocolate chip cookie contains 110 calories. A random sample of 15different brands of 1-ounce chocolate chip cookies resulted in the following calorie amounts. Atthe a = 0.01 level, is there sufficient evidence that the average calorie content is greaterthanm110 calories?100125150125155140150145135160160120185100110

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2. The Medical Rehabilitation Education Foundation reports that the average cost of rehabilitation for stroke victims is $24,672. To see if the average cost of rehabilitation is different at a particular hospital, a researcher selects a random sample of 35 stroke victims at the hospital and finds that the average cost of their rehabilitation is $26,343. The standard deviation of the population is $3251. At a = 0.01, can it be concluded that the average cost of stroke rehabilitation at a particular hospital is different from $24,672?

2. The Medical Rehabilitation Education Foundation reports that the average cost of rehabilitation for stroke victims is $24,672. To see if the average cost of rehabilitation is different at a particular hospital, a researcher selects a random sample of 35 stroke victims at the hospital and finds that the average cost of their rehabilitation is $26,343. The standard deviation of the population is $3251. At a = 0.01, can it be concluded that the average cost of stroke rehabilitation at a particular hospital is different from $24,672?

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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0.05 level of significance. Solve for appropriate test statistic and show written work!
The test of significance is 2.060
Salma claimed that the gas price in Blue Park neighborhood (mean of $3.65) is higher than that in Green Spring (mean of $3.59). She obtained the t-value of 2.223 after calculating data from 6 gas stations in Blue Park and 5 gas stations in Green Spring. Use the chart below and determine if Salma's claim is supported! Table 10-3. Critical values of "t" significance level p= 0.05 significance level p= 0.01 TP 1 12.706 63.657 2 4.303 9.925 3 3.182 5.841 2.776 4.604 5 2.571 4.032 6 2.447 3.707 7 2.365 3.499 2.306 3.355 9 2.262 3.250 10 2.228 3.169 11 2.201 3.106 Copy the following into your text box, fill in the blanks, and answer the questions A. The degree of freedom is: B. The t-calculated value is: and the t-critical value is : C. Comparison: t-calc t-crit (answer with ()) D. Is the null hypothesis accepted or rejected? Explain how you determined that! Also, explain what it means to reject or accept the hypothesis! E. Explain if Salma's claim is supported based on your t-value…
The summary statistics are n=85, x=3.93, s=0.63. Use a 0.01 significance level to test the claim that the population of student course evaluations has a mean equal to 4.00. identify null/ alt hypothesis, test statistic, P- value, and state final conclusion that addresses the original claim
A professional marketing survey involves product recognition in New York and California. Of 558 New York residents surveyed, 193 knew the product while 179 out of 614 Californians knew the product. 1. Test the claim that the recognition rates are greater in New York. 2. In which state does the product need the most help with name recognition? Use the given data to compare mean age of residents in Seaside and Marina. Sample Data * = 43.2 yr s = 4.7 yr n = 97 Seaside Before After 1. Test the claim that the mean age of seaside residents is equal to the mean age of Marina residents. 2. How would the result change if we use a = 0.01? Matched Pairs: Write the alternative hypothesis H₁, for each claim: 1. New engine management software will increase the gas mileage in your car. 2. My coaching will reduce your golf score. Difference An instructor gives a test before and after a lesson with these results from randomly selected students Before and After Data 54 70 = 61 Marina 56 s = 6.7 year…
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I understand how the level of signficance = 1.96 and I understand: Ho:μ=5 - Ha:μ<5 But I need help understanding how to calculate the test statistic. I know we have a sum of 93 with a sample size of 28 but how do you come to the conclusion for the test stastisic and how do you figure out whether you have enough proof to accept or reject the claim? Thank you.