2. Obtain the complete power triangle for the following parallel-connected loads: a. 5 kW, pf = 0.80 lagging b. 4 kVA, 2kvar (capacitive) c. 6 kVA, pf = 0.90 lagging S=. P =. p.f = pf angle, 0= Answers S= 14.535/17.477° k VA p=13 864 kW 8 =4365 KVAR (inductive pf = 095 lagging Gr= 1704770

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Current Division Method

The generalized current divider formula is given by the following relation below,