2. For a 6x4 ft two-dimensional body shown in the figure, determined the nodal temperatures.Take the thickness 0.1 ft.q = 160 Btu/(h.ft²)3h= 30 Btu/(h.ft.°F)T= 50 °FT= 150 °F12.Q = 300 Btu/(h.ft')%3DKx = Kyy = 25 Btu/(h.ft. F)%3D2)

Data Given: kxx=kyy=25 Btu(h.ft.°F)h=30 Btu(h.ft2.°F)T∞= 50°Fq=160 Btu(h.ft2)Q=300Btu(h.ft2)T=150°F…

Answered: 2. For a 6x4 ft two-dimensional body…

2. For a 6x4 ft two-dimensional body shown in the figure, determined the nodal temperatures. Take the thickness 0.1 ft. T= 150 °F q=160 Btu/(h.ft²) 2 3 2 h=30 Btu/(h.ft². °F) T-50 °F

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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