2. Design the steel requirements for a 7 m, 600 mm X 600 mm square tied column, as shown in the Figure below, in an unbraced frame. The effective length factor is 1.0. Use fc = 20.7 MPa, fy = 413.7 MPa and place the bars in the two end faces only with d' = 75 mm. Use NSCP 2001. Use conservative formula for El. Use load combination of 0.75 (1.4DL +1.7LL +1.7WL). Pa-850 KN Pu= 900 KN PNL = 150 KN fr M = 200 kN-m Max = 140 kN-m M₁-180 kN-m MpL = 30 kN-m My = 40 ky-m MWL = 80 kN-m braced frame unbraced from (a) due to gravity load. (6) due to wind Load

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
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Chapter2: Loads On Structures
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2. Design the steel requirements for a 7 m, 600 mm X 600 mm square tied column,
as shown in the Figure below, in an unbraced frame. The effective length factor is
1.0. Use f'c = 20.7 MPa, fy = 413.7 MPa and place the bars in the two end faces
only with d' = 75 mm. Use NSCP 2001. Use conservative formula for El. Use load
combination of 0.75 (1.4DL +1.7LL +1.7WL).
Pa-850 KN
P900 KN
PWL = 150 KN
MWL = 200 kN-m
MOL = 140 KN-m
M-180 KN-m
MDL 80 KN-m
My = 40 kN-m
MWL 80 KN-m
braced frame
unbraced frame
(a) due to gravity load.
(b) due to wind load
Transcribed Image Text:2. Design the steel requirements for a 7 m, 600 mm X 600 mm square tied column, as shown in the Figure below, in an unbraced frame. The effective length factor is 1.0. Use f'c = 20.7 MPa, fy = 413.7 MPa and place the bars in the two end faces only with d' = 75 mm. Use NSCP 2001. Use conservative formula for El. Use load combination of 0.75 (1.4DL +1.7LL +1.7WL). Pa-850 KN P900 KN PWL = 150 KN MWL = 200 kN-m MOL = 140 KN-m M-180 KN-m MDL 80 KN-m My = 40 kN-m MWL 80 KN-m braced frame unbraced frame (a) due to gravity load. (b) due to wind load
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