2. Application of Newton's Laws. An 8-kg box and a 10-kg box that are attached by a rope that passes over a frictionless pulley slide on an inclines with friction (uk=0.1). 8 kg 10 kg Find the acceleration of the boxes and the tension in the 40° 50° rope.
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- A person doing a chin-up weighs 700 N, exclusive of the arms. During the first 25.0 cm of the lift, each arm exerts an upward force of 355 N on the torso. If the upward movement starts from rest, what is the persons velocity at that point?Suppose au airline allows a maximum of 30 kg for each suitcase a passenger brings along. (a) What is the weight in newtons of a 30-kg t1ikasr? (b) What is the weight in pounds?Ina traction setup a broken bone, with pulleys and rope available, how might we be able to Increase the force along the tibia using the weight? (See Figure 4.30) (Note that the tibia is the shin bone shown in this image.) Figure 4.30 A leg is suspended by a traction system in which wires used to transmit forces. Frictionless pulleys crw.ge the direction of the force T without changing Its magnitude.
- 23. What is the accelerallof U tIT system? 3.NZ 24. What is the tension on the string? 2 howmor In the following diagram, block B weighs 711 N. The coefficient of static friction between the block and the table is 0.35, and the angle 0 is 30 degrees, assume that the cord between B and the knot is horizontal Ma tan 30 Bo 25. Find the static frictional force ? M. -7.24, 7/1 26. Find the maximum weight of block A for which the system 1-72:5g 98 T Ti కి 1/ will still be stationary. Al m 7, A 5000 kg dump truck has a maximum 400 hp (1 hp 746 W), and it is moving up on an inclined roa slope of 15 degrees. If the frictional coefficient on the road is 0.80, what is the max constant speed that ucker can maintain on the inclined? F v4. The 1.0 kg physics book in ngure is connected by a string to a 500 g cof ch un the slope and relcased with a speed of 3 m/s. The cocefficient of fri a) What is the acceleration of the objects? b) Draw a force diagram for an individual item. Find the tension in the rop analyze?) ans 6.73 m s', 1.54 N 204. An elevator (mass 4850 kg) is to be designed so that the maximum acceleration is 0.0680g. What are the maximum and minimum forces the motor should exert on the supporting cable? : blodged or 11.agli 31 voted 4 DAS to mumixa bosted we pad report AS 5. A load whose mass is 15.0 kg is lowered vertically by a rope. In a given instant, the tension in the rope is 170 N. What is the acceleration of the load? Is it UP, or DOWN? el molenst eritti und to y eqot of Jaloud gil-28 a Mil os hosu gniad el eggs A.C entvom al 31 88.8 begin gated walls bris Jas in betite Soxoud ont acol vo M 388 6. A 1200-kg car starting from rest reaches a speed of 60 mi/h meleons edi Felo S.C in 52.0 s. (a) What is its acceleration (m/s²)? (b) What force is acting upon it? ****Note: 1 mi/h = 0.447 m/s
- 2. A 75.0-kg man stands on a weighing scale in an elevator. Calculate thescale reading if the elevator moves upward at a constant speed of 1 m/s. 3. The coefficient of static friction between Teflon and scrambled egg isabout 0.04. What is the smallest angle from the horizontal that will causethe eggs to slide across the bottom of a Teflon-coated skillet? 4. A house is built on the top of a hill with a nearby 45⁰ slope. Anengineering study indicates that the slope angle should be reducedbecause the top layers of soil along the slope might slip past the lowerlayers. If the static coefficient of friction between two such layers is 0.50,what is the least angle ф through which the present slope should bereduced to prevent slippage?Chloe is helping Tina move. Tina has to load a 265 kg box of chocolates and coffee up an incline of 25o, which also has a coefficient of static friction of 0.50. Chloe applies a force on the box at an angle of 30o with respect to the ramp. What is the minimum force needed to slide the box up the ramp? I know the answer is 2037.93N 30degrees up respect to the ramp but I dont know the steps to solve it.3. A block of mass m = 5.9 kg is pulled up a 0 = 21° incline as in the figure below with a force of magnitude F = 37 N. (Hint: remember to measure all angles from +x axis.) y a. Draw a free body diagram showing all the forces. NORml Fte F Mass = 5.9k 0-21° F-37N there b. Determine the x and y components of all the forces. X Components of Force f = 37 N Y comporents of Force F=0N X componnt of normal force=ON * Componis of weight=-5.9x 9.8x Sin 210=70. FJN Y Comperents of weight=5.9a 9.8 x Casal. - 53.98 Y Compenents of normal force=mglos H%53.98, c. Write equations summing all the x components and all the y components. F-mg Sm@= mxa 37-20.72= 5.9x a 2.7l6 = Comporunts) Normal force - mg les 0: 05 53.98-53.98-0o d. Find the acceleration of the block if the incline is frictionless. (Give the magnitude of the acceleration. Find the acceleration of the block if the coefficient of kinetic friction between the block and incline is 0.12. (Give the magnitude of the acceleration.) е. 3
- M Alt Alt LATITUDE E6430 Name: Directions: All problems must be solved using the problem-solving method, givens, unknowns, equation, cubstitution, and solve with correct unit to receive full credit. Also, all force problems require an FBD. P.4D-Practice-Force of Friction 1. A 38 kg crate rests on a floor. A horizontal pulling force of just more than 170 N is needed to start thecrate moving. What is the coefficient of static friction between the crate and the floor?what is minimum coelticrent of stame friction hassary to keep Jkg given a = 10° ? Y box stationary on the s slide Reg. 494.99 SAVE $100 SAVE $100 Reg. $899.99 Length A Given ladder L = 3.75m Lareight ladder The Coefifficient of Static friction between The ladder and the floor as µ5x = 0.25 The wethcreat of Show c fore mon beteemn ladder and wall Mxy=0.5 - what is minimum angle the ladder can be fitted at before its slips? = 200 N4. The 5000-N concrete block is adjusted its positionusing a 5° wedge under the action of force F. If thecoefficient of static friction between all contacts is0.3, determine the least force F required to movethe block.