3. A block of mass m = 5.9 kg is pulled up a 0 = 21° incline as in the figure below with a force of magnitude F = 37 N. (Hint: remember to measure all angles from +x axis.) a. Draw a free body diagram showing all the forces. NOtmal Flle F Mass = 5.gk 0-21° F-37N there b. Determine the x and y components of all the forces. X Comfonents of Force F= 37N y componenis of Force F=ON X Componnt of normal foce * Compons of weight=-5.9x 9.8x Sm 21070. 7IN Y.comperents of We.gh= S.9a 9.8 x Casal: - 53.98 Y Com fonents of normal force- c. Write equations summing all the x components and all the y components. F-mg Sm@= mxa 37-20.7as 5.9 x a 27le * =a -(x Comporunts) 53.98-53.980 Nor mal force - mg les 0: 0 d. Find the acceleration of the block if the incline is frictionless. (Give the magnitude of the acceleration. Find the acceleration of the block if the coefficient of kinetic friction between the block and incline is 0.12. (Give the magnitude of the acceleration.) е.

A child of mass 43 kg stands on a scale inside an elevator. Select one or more: A. The scale would show his weight as 335.40 N when the elevator accelerates downward at 2 m/s2. B. The scale would show his weight as 507.4 N when the elevator accelerates upward at 2 m/s2. C. The scale would show his weight as 335.40 N when the elevator accelerates upward at 2 m/s2. D. The scale would show his weight as 335.40 N when the elevator decelerates upward at 2 m/s2. E. The scale would show his weight as 421.4 N when the elevator is stationary. F. The scale would show his weight as 335.4 N when the elevator decelerates upward at 2 m/s2. G. The scale would show his weight as 421.40 N when the elevator moves with a constant velocity of 2.5 m/s.

You are standing still on a bathroom scale. The scale shows your weight 140 lbs. How much is the support force?   A. 140 x 9.8 m/s^2   B. ZERO   C. 140N   D. 140 lbs

In the figure, the net external force on the 24 kg mower is known to be 51 N. f=28N v=1.8 m/s   a. If the force of friction opposing the motion of 28N what force in newtons is the person acting on the mower? b. Suppose the mower is moving at 1.8 m/s when the force F is removed. How far will the mower go before stopping in m?