2. An object with a height of 12 mm is projected by an objective as a real image of 48 mm. The image plain is in a distance of 260 mm right from the object plain. Find the effective focal length of the objective, if the distance between its principle plains AHH = 10 mm.

The focal length of a lens is 5.00 cm. How fare from the lens must the object be to produce an image 1.50 cm from the lens?

Calculate the magnification of an object placed 6.20 mm from a compound microscope that has a 6.00 mm focal lengthobjective and a 50.0 mm focal length eyepiece. The objective and eyepiece are separated by 23.0 cm.

The near point of a person's eye is 60.0 cm. What is the approximate power of the correcting lens that allows the person to clearly see objects placed 30.0 cm away? Neglect the eye-lens distance. O (A) -5.00 diopters O (B) -1.67 diopters C (C) +1.67 diopters O (D) +5.00 diopters Need Help? Read It

2. A 5 cm high object is 12.0 cm in front of a system of two lenses, with f, = 10.0 cm and f2 = -15.0 cm. The lenses are separated by d = 20.0 cm. (a) How far is the final image FROM THE CONVEX LENS and (b) on which side is it formed and (c) what is the size of the final image? 12.Ocm

Problem 10:  A simple compound microscope with an overall magnification of -550 has an objective that magnifies by -250. Part (a)  What is the magnification of the eyepiece? Part (b)  If there is another objective that can be used, having magnification of -400, what other total magnification is possible?

can someone help me with this physics problem

When you hold an insect at the near point of your eye it subtends an angle of 5.00  10-3 rad. Determine the angular size (magnitude only) of the insect when viewed through a microscope that has an angular magnification with a magnitude of 165.

A microscope has an objective lens with a focal length of 16.22 mm and an eyepiece with a focal length of 9.92 mm. With the length of the barrel set at 34.0 cm, the diameter of a red blood cell's image subtends an angle of 1.43 mrad with the eye. If the final image distance is 34.0 cm from the eyepiece, what is the actual diameter of the red blood cell? Hint: To solve this equation, go back to basics and use the thin-lens equation.

An individual is nearsighted; his near point is 18.0 cm and his far point is 42.0 cm. (a) What lens power is needed to correct his nearsightedness? diopters (b) When the lenses are in use, what is this person's near point? cm