Calculate the magnification of an object placed 6.20 mm from a compound microscope that has a 6.00 mm focal lengthobjective and a 50.0 mm focal length eyepiece. The objective and eyepiece are separated by 23.0 cm.

A transparent photographic slide is placed in front of a converging lens with a focal length of 2.53 cm. An image of the slide is formed 12.0 cm from the slide. (a) How far is the lens from the slide if the image is real? (Enter your answers from smallest to largest starting with the first answer blank. Enter NONE in any remaining answer blanks.) cm cm (b) How far is the lens from the slide if the image is virtual? (Enter your answers from smallest to largest starting with the first answer blank. Enter NONE in any remaining answer blanks.) cm cm Need Help? Master It

A microscope has an objective lens with a focal length of 16.22 mm and an eyepiece with a focal length of 9.92 mm. With the length of the barrel set at 34.0 cm, the diameter of a red blood cell's image subtends an angle of 1.43 mrad with the eye. If the final image distance is 34.0 cm from the eyepiece, what is the actual diameter of the red blood cell? Hint: To solve this equation, go back to basics and use the thin-lens equation.

A thin converging lens has a focal length of 8.00 cm. If a real, inverted image is located 12.0 cm from the lens, where is the object located? What is the magnification?

A lab technician with a near point of 27 cm is viewing a specimen with a compound microscope that has a barrel length of 16.6 cm and an eyepiece that has a focal length of 1.5 cm. Determine the focal length the objective must have so that the overall magnification of the microscope will be -291. cm

1) Calculate the magnification of the 36-in refractor at Lick Observatory on Mount Hamilton near San Jose, California. The focal lenght of the objective lens is 17.37m, and the focal lenght of the eyepiece is 22 mm. (Express your answer to three significant figures.) 2) What is the significance of the negative sign in the magnification equation?       a) The image is inverted when viewed in the eyepiece.        b) The image is upright when viewed in the eyepiece.

In a compound microscope, the focal length of the objective is 4.15 cm and that of the eyepiece is 7.07 cm. The distance between the lenses is 23.5 cm. (a) What is the angular magnification of the microscope if the person using it has a near point of 29.3 cm? (b) If, as normal, the first image lies just inside the focal point of the eyepiece, as in the drawing, how far is the object from the objective? (c) What is the magnification (not the angular magnification) of the objective?

A microscope has an eyepiece with a focal length of 18.0 mm, and an objective with a focal length of 8.00 mm. Thelenses are separated by 19.7 cm. A) If the final image is located infinitely far away, where is the object located? B) What is the total magnification?

A microscope has an objective lens with a focal length of 16.22 mm and an eyepiece with a focal length of 9.06 mm. With the length of the barrel set at 33.0 cm, the diameter of a red blood cell's image subtends an angle of 1.43 mrad with the eye. If the final image distance is 33.0 cm from the eyepiece, what is the actual diameter of the red blood cell? Hint: To solve this equation, go back to basics and use the thin-lens equation. ?m

A microscope has an objective lens with a focal length of 16.22 mm and an eyepiece with a focal length of 9.28 mm. With the length of the barrel set at 35.0 cm, the diameter of a red blood cell's image subtends an angle of 1.43 mrad with the eye. If the final image distance is 35.0 cm from the eyepiece, what is the actual diameter of the red blood cell? Hint: To solve this equation, go back to basics and use the thin-lens equation. um