2. Among births, is the proportion of males the same as the proportion of females? A random sample of births in a major metropolitan area found 1345 boys among 2546 children. A 99% confidence interval for p= the true proportion of male births in this population is (0.5028, 0.5538). (a) Based on the confidence interval, is there convincing evidence that the true proportion of male births in this population differs from 0.5? Explain. (b) What information is provided by the confidence interval that would not be provided by a significance test?

We wish to estimate what percent of adult residents in a certain county are parents. Out of 600 adult residents sampled, 228 had kids. Based on this, construct a 90% confidence interval for the proportion � of adult residents who are parents in this county. < � <

The mean score on the math portion of the ACT for the year 2000 is μ = 20.7. A sample of 20 students in a local school district had a mean of 22.95. Using the sample, a 95% confidence interval estimate for the mean is (20.76, 25.14).  State the point estimate for the mean ACT score for students. Based on this sample information , do you believe that the local students have a mean different from the general population? Why?     22.95 is in the center of the interval. The means are definitely not different.     22.95 is just outside the 95% confidence interval. Can't say the means are really different.     22.95 is not equal to 20.7. The means are definitely different.     20.7 is just outside the 95% confidence interval. Can't say the means are really different.

We wish to estimate what percent of adult residents in a certain county are parents. Out of 200 adult residents sampled, 34 had kids. Based on this, construct a 90% confidence interval for the proportion, p, of adult residents who are parents in this county. Give your answers as decimals, to three places.

I want to estimate the population mean number of times that adults eat breakfast in a week. I spoke with 12 coworkers, and the numbers were 7, 5, 5, 7, 2, 3, 7, 5, 1, 0, 7, 6. Calculate a 95% confidence interval for the population mean (round 3 decimal places).

We randomly sample 600 people in a specific town. 342 of them like cats. Based on this, construct a 95% confidence interval for the true population proportion of people in this town who like cats. Give your answers as decimals, rounded to four places.

If n=550 and p' (p-prime) = 0.19, construct a 90% confidence interval.Give your answers to three decimals.