2. (a) Write a function, called myListFn, which takes a single argument n and implements the following algorithm: 1. Simulate n independent numbers, denoted x = (x1, r2, ..., xn), from the N(0, 1) distribution. 2. Calculate the mean X = =1"j 3. If x > 0, then simulate n independent numbers, denoted y = (yı, y2, ..., Yn), from the exponential density with mean X. If x < 0, then simulate n independent numbers, denoted z = (21, 22, ..., zn), from the exponential density with mean -X. Set y = (yı, Y2, ... Yn) = -z. 4. Calculate k which is the number of j with y;| > ]xj/. 5. Return the list of x, y and k with names xVec, yVec and count respectively. %3D n. (b) Execute the following lines and check the format of the answers: lapply( rep(10,4), myListFn ) sapply( rep(10,4), myListFn ) Note that sapply is effectively lapply followed by simplify2array. If myListFn has no arguments, then similar results can be obtained with replicate(4, myListFn()) and replicate (4, myListFn(), simplify=F). Now for a simulation study. Use lapply to call the function myListFn with n = 10 for 1,000 times. So the output consists of 10,000 values for a denoted {rij: i = 1, 2,..., 1,000;j = 1, 2, ..., 10}; 10,000 values for y denoted {yij: i = 1,2, ..., 1,000; j = 1,2, ..., 10}; and 1,000 values for n denoted n1, n2, ..., n1000- Denote the output by myList. This output is used in the remaining parts of this question. (c) Extract all the vectors with the name yVec. The result should be a list of 1000 vectors. (d) Extract all the vectors with the name yVec. The result should be a 10 x 1000 matrix with one column for each of the vectors yVec. (e) Create a list which is identical to myList but all the components called count have been removed. (f) Pick out those lists in myList which are such that count is greater than 2.

Consider the following function shoots : def shoots(x: int) -> int: if x <= 0: return 0 4 elif x == 1: return shoots(x + 2) 6 elif x == 2: return shoots(x - 1) 80 elif x == 2: 9. return -1 10 else: 11 return shoots(x - 2) 2 3

Program Assignment07implicit noneinteger, parameter :: n = 1000  ! maximum iterationreal(kind=8), parameter :: EPSILON = 1.d-3real(kind=8):: x0,xinteger:: iterationx0=3.0d0call solve(f(x),fp(x),x0,n,x,iteration)   contains real (kind=8) function f(x)  ! this is f(x)implicit nonereal (kind=8), intent(in)::xf=x**2.0d0-1.0d0end function f real (kind=8) function fp(x)  ! This is f'(x)implicit nonereal (kind=8), intent(in)::xfp=2.0d0*xend function fp end program Assignment07 modify this program in fortran byy adding a module (called Newton) which contains subroutinesolve. You should develop subroutine solve based on the aforementioned Newton's method. ▪ Function f(x) is x2-1 whose zero is known. Set the input argument EPSILON to 1.E-3 and inputargument n to 1000 when you call subroutine solve and run the program Modify the function to one that is known not to have zeros; e.g. (x2+1)

For input vector x, write a function to check whether there exists at most 5 elements in x whose values are less than 7.

In Python, Compute the: sum of squares total (SST), sum of squares regression (SSR), sum of squares error(SSE), and the r, R^2 values. You can use the sum() and mean() built-in functions. Here are the x and y values to use. x = [-5,-1,3,7,5,10] y = [-10,-3,5,8,7,10]

can anyone please solve this questions asap?

Given a string containing only parentheses (, ), {, }, [, and ], determine if the input string is valid. An input string is valid if: Open brackets must be closed by the same type of brackets. Open brackets must be closed in the correct order. Write a function isValidParentheses that takes in a string s and returns a boolean value indicating whether the parentheses in s are valid. Example: Input: s = "{[()]}" Output: true Input: s = "{[()]}" Output: false Input: s = "{[(])}" Output: false Input: s = "{[()]}()[]" Output: true Note: The input string will only contain the characters (, ), {, }, [, and ]. An empty string is considered valid.

The MATLAB function arg supports variable arguments, returns the sum of the number of arguments and all arguments, and has a help function. Write the arg so that the next execution results.   >> help argIt supports variable arguments. >> [n,m] = arg(5,6)n =    2m =    11>> [n, m] = arg(3,4,5)n =   3m =   12

vector, or a matrix in the same way as described for rand function. EXERCISE I8 Generate a random integer between I and 10. Ask user to guess the number. If user's guess is incorrect, ask' to guess again until user gets it right. At this point, tell user that he guessed it correctly and print out the number of attempts it took for the correct guess. Output Samples >> exercisel8 Please guess an integer between 1 and 10: 5 Your guess is incorrect. Please try again: 2 You guessed it correctly in 2 attemptS >> >> exercise16 Please guess an integer between 1 and 10: 2 Your guess is incorrect. Please try again: 3 Your guess is incorrect. Please try again: 6 Your guess is incorrect. Please try again: 5 Your guess is incorrect. Please try again: 8 Your guess is incorrect. Please try again: 9 Your guess is incorrect. Please try again: 10 Your guess is incorrect. Please try again: 1 Your guess is incorrect. Please try again: 4 Your guess is incorrect. Please try again: 7 You guessed it correctly…

python help... Write a function justVowels() that takes a string as a parameter and returns a new string that contains all the vowels found in the parameter string. The vowels in the returned string should appear in the same order as they did in the parameter string. A vowel is one of a, e, i, o, or u. both the upper- and lower-case vowels should be included. The characters in the returned string should have the same capitalization as they did in the parameter string. If the function is given a string without any vowels or an empty string, it should return the empty string. Use the if-else condition with iterate loop pattern. Don’t forget to include the docstring and comments.    How it should run... >>> justVowels('Did you include your collaboration statement') 'iouiueouoaoaioaee' >>> justVowels('If you did not include your collaboration statement no points') 'Iouioiueouoaoaioaeeooi' >>> justVowels('1,2,3,4,...') '' >>> justVowels('') ''