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College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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An air-filled parallel-plate capacitor has plates of area 2.60 cm separated by 3.00 mm. The capacitor is connected to a 9.0-V battery.
(a) Find the value of its capacitance.
pF
(b) What is the charge on the capacitor?
рс
(c) What is the magnitude of the uniform electric field between the plates?
Enter a number. differs significantly from the correct answer. Rework your solution from the beginning and check each step
carefully. V/m"
Transcribed Image Text:2
An air-filled parallel-plate capacitor has plates of area 2.60 cm separated by 3.00 mm. The capacitor is connected to a 9.0-V battery.
(a) Find the value of its capacitance.
pF
(b) What is the charge on the capacitor?
рс
(c) What is the magnitude of the uniform electric field between the plates?
Enter a number. differs significantly from the correct answer. Rework your solution from the beginning and check each step
carefully. V/m
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- Extra: How is the dielectric constant defined relative to Eplates, Edielectric, and/or Enet?arrow_forwardPart A The voltage across a 4 μF capacitor increases by 48 V. If the final charge on the capacitor is 507 μC, determine the initial charge. Q₁ = Part B Two parallel plates each have a charge magnitude of 601 nC. Between the plates is a dielectric with K = 86. Additionally, the E-field between the plates is 7.81x105 V/m. Determine the area of each plate. A= Part C A capacitor with no dielectric has an E-field of 88 kV/mm between the plates. The area of each plate is 46.3 cm² and the voltage across the capacitor is 1.5 V. Determine the capacitance. C=arrow_forwardA parallel-plate capacitor is constructed using a dielectric material whose dielectric constant is 3.30 and whose dielectric strength is 1.20 x 108 V/m. The desired capacitance is 0.300 μF, and the capacitor must withstand a maximum potential difference of 4.00 kV. Find the minimum area of the capacitor plates. m²arrow_forward
- An air-filled parallel-plate capacitor has plates of area 2.50 cm^2 separated by 1.80 mm. The capacitor is connected to a(n) 13.0 V battery. a) Find the value of its capacitance. pF b) What is the charge on the capacitor? pC c) What is the magnitude of the uniform electric field between the plates? N/Carrow_forwardConsider a parallel-plate capacitor having an area of 2550 mm^2 and a plate separation of 4.9mm and with a material of dielectric constant 5.9 positioned between the plates. Also, the value of E0 is 8.85x10^-12F/m. a) What is the capacitance of this capacitor in pF? b) compute the electric field that must be applied for a charge pf 7.8x10^-8C to be stored on each plate in V/m.arrow_forwardA2.50-cm-diameter parallel-plate capacitor with a spacing of 0.900 mm is charged to 400 V Y ▼ Part A What is the total energy stored in the electric field? Express your answer with the appropriate units. Uc= Part B Submit Request Answer HA up Value Submit What is the energy density? Express your answer with the appropriate units. HA Value → Request Answer Units 20 BARCE ? BANC Units ?arrow_forward
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