Answered: 2 Ag+(aq) + Fe(s) + 2…

2 Ag+(aq) + Fe(s) + 2 OH-(aq) --> Fe(OH)2(s) + 2 Ag(s) Ag+ = 1.03 M Fe = 2.255 g OH- = 0.100 M Fe(OH)2 = 0.50 mole Ag = 2.2 x 1022 atoms E = E° - (0.0592/n)log(Q) E°red = E°ox =

Chemistry: Principles and Reactions

8th Edition

ISBN:9781305079373

Author:William L. Masterton, Cecile N. Hurley

Publisher:William L. Masterton, Cecile N. Hurley

Chapter15: Complex Ion And Precipitation Equilibria

Section: Chapter Questions

Problem 40QAP

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Question

Question 3 options:

2 Ag⁺_(aq) + Fe_(s) + 2 OH^-_(aq) --> Fe(OH)_2(s) + 2 Ag_(s)

Ag⁺ = 1.03 M

Fe = 2.255 g

OH^- = 0.100 M

Fe(OH)₂ = 0.50 mole

Ag = 2.2 x 10²² atoms

E = E° - (0.0592/n)log(Q)

E°_red =

E°_ox =

E°_total =

n =

Q =

E =

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