Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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**Problem:**

If 5.0 mL of 0.00200 M Fe(NO₃)₃ is diluted to 50.0 mL, what is the concentration of Fe³⁺ in the diluted solution?

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**Solution Explanation:**

To find the concentration of Fe³⁺ after dilution, you can use the dilution formula:

\[ C_1V_1 = C_2V_2 \]

Where:
- \( C_1 \) is the initial concentration (0.00200 M)
- \( V_1 \) is the initial volume (5.0 mL)
- \( C_2 \) is the final concentration
- \( V_2 \) is the final volume (50.0 mL)

Substituting the known values:

\[ (0.00200 \, \text{M}) (5.0 \, \text{mL}) = C_2 (50.0 \, \text{mL}) \]

\[ 0.010 \, \text{M} \cdot \text{mL} = C_2 \cdot 50.0 \, \text{mL} \]

\[ C_2 = \frac{0.010}{50.0} \]

\[ C_2 = 0.00020 \, \text{M} \]

Thus, the concentration of Fe³⁺ in the diluted solution is 0.00020 M.
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Transcribed Image Text:**Problem:** If 5.0 mL of 0.00200 M Fe(NO₃)₃ is diluted to 50.0 mL, what is the concentration of Fe³⁺ in the diluted solution? --- **Solution Explanation:** To find the concentration of Fe³⁺ after dilution, you can use the dilution formula: \[ C_1V_1 = C_2V_2 \] Where: - \( C_1 \) is the initial concentration (0.00200 M) - \( V_1 \) is the initial volume (5.0 mL) - \( C_2 \) is the final concentration - \( V_2 \) is the final volume (50.0 mL) Substituting the known values: \[ (0.00200 \, \text{M}) (5.0 \, \text{mL}) = C_2 (50.0 \, \text{mL}) \] \[ 0.010 \, \text{M} \cdot \text{mL} = C_2 \cdot 50.0 \, \text{mL} \] \[ C_2 = \frac{0.010}{50.0} \] \[ C_2 = 0.00020 \, \text{M} \] Thus, the concentration of Fe³⁺ in the diluted solution is 0.00020 M.
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