Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
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A composite member is made of a hollow brass cylinder (E = 105 GPa, v= 0.32, and a = 20.0x10/°C)
interference fit over ASTM-A242 solid steel rod (E = 200 GPa, v= 0.3, and a = 11.7x10/C). The outer
radius of brass is 100 mm, the inner radius is 50 mm, and the outer radius of steel is 50.05 mm. The length
of both is the same (This implies NO STRESS CONCENTRATION FACTOR involved).
Compute (a) the total radial interference of the brass and (b) the temperature difference AT required to
easily slip the brass cylinder over the steel rod. For easy insertion, allow a clearance of ½&, see slide 16
of Lecture 9 notes. (Hint: First calculate total interference (8 + ½8), then use definition of a (defined in
Lecture 6, slide 26).
(c) Compute the interface pressure p of the interference fit at room temperature (use the actual radial
interference for this; that is, without clearance).
%3D
Fig. 2
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Transcribed Image Text:(2) A composite member is made of a hollow brass cylinder (E = 105 GPa, v= 0.32, and a = 20.0x10/°C) interference fit over ASTM-A242 solid steel rod (E = 200 GPa, v= 0.3, and a = 11.7x10/C). The outer radius of brass is 100 mm, the inner radius is 50 mm, and the outer radius of steel is 50.05 mm. The length of both is the same (This implies NO STRESS CONCENTRATION FACTOR involved). Compute (a) the total radial interference of the brass and (b) the temperature difference AT required to easily slip the brass cylinder over the steel rod. For easy insertion, allow a clearance of ½&, see slide 16 of Lecture 9 notes. (Hint: First calculate total interference (8 + ½8), then use definition of a (defined in Lecture 6, slide 26). (c) Compute the interface pressure p of the interference fit at room temperature (use the actual radial interference for this; that is, without clearance). %3D Fig. 2
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