(2) A composite member is made of a hollow brass cylinder (E 105 GPa, v= 0.32, and a = interference fit over ASTM-A242 solid steel rod (E = 200 GPa, v= 0.3, and a = 11.7x10/°C). The outer radius of brass is 100 mm, the inner radius is 50 mm, and the outer radius of steel is 50.05 mm. The length of both is the same (This implies NO STRESS CONCENTRATION FACTOR involved). Compute (a) the total radial interference of the brass and (b) the temperature difference AT required to easily slip the brass cylinder over the steel rod. For easy insertion, allow a clearance of ½&, see slide 16 of Lecture 9 notes. (Hint: First calculate total interference (8 + ½8), then use definition of a (defined in Lecture 6, slide 26). (c) Compute the interface pressure p of the interference fit at room temperature (use the actual radial interference for this; that is, without clearance). 20.0x10*/°C) Fig. 2

(2) A composite member is made of a hollow brass cylinder (E 105 GPa, v= 0.32, and a = interference fit over ASTM-A242 solid steel rod (E = 200 GPa, v= 0.3, and a = 11.7x10/°C). The outer radius of brass is 100 mm, the inner radius is 50 mm, and the outer radius of steel is 50.05 mm. The length of both is the same (This implies NO STRESS CONCENTRATION FACTOR involved). Compute (a) the total radial interference of the brass and (b) the temperature difference AT required to easily slip the brass cylinder over the steel rod. For easy insertion, allow a clearance of ½&, see slide 16 of Lecture 9 notes. (Hint: First calculate total interference (8 + ½8), then use definition of a (defined in Lecture 6, slide 26). (c) Compute the interface pressure p of the interference fit at room temperature (use the actual radial interference for this; that is, without clearance). 20.0x10*/°C) Fig. 2

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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