(2) * 28" 2#8 14" I2.5" NwC fé=3000 psi > 2 #10 z 2 #11 I 3" Grade 60 steel &Mn = ?

Please solve 3 and 4 respectively!

Compression Steel  Given: The beam cross-section shown have the following cross-sectional properities:  f'c = 4000 psi  Find phi Mn.

Compression steel Given: The beam cross-section shown have the following cross-sectional properties:  f'c = 4000 psi  Find phi Mn.

Find Mn?

(1) (2) 24" (3) 4#7 12" 4#8 12% 4 #9 14" 41 3" 18.5" L 2.5 opening I 2,5" 14" 4" 21" nobuje to 4 3" 3" 4#9 fó= 4000 psi NWC Grade 60 Steel. & Mn = ? fé=3000 psi Grade 60 steel, Tied Bars. &Mn = ? fé= 4ksi. NWC Grade 60 steel, Tied Bars. & Mn = ? 21" NwC 13" fe= 3 ksi Nwc Grade 60 steel & Mn = ?

Derive the maximum steel ratio and the recommended rteel ratio fe' O.856 fy Po-004 3 0.85 fc' pooos= 0-85

Answer the following for the section at Point D Only Calculate the distributed load "w" that: Will cause the section crack Will cause the reinforcement to yield. Material Properties: F'c = 5000 psi Fy = 60000 psi Es = 29000000 psi Ln = 27 ft L wl₂² 16 wl,² 14 CD L wl,2 vl₁² 10 11 win² 16 h: 28 in A=4 in² b=14 in n d: 25 in

Problem 4 Given two welded plates n A36 plates t= 3/ • fillet size w=1/4" Electrode Fexx= 70 ksi • plate width = 9" ● ● ↑ t=¾/2" = 2) = Pu= smaller of (1) A(2) w=1/4" Base Metal Strength, DRn is given by: ÞRn = 0.75(0.6Fu) (tBM)(Lw) t=3/8" Determine max Pu that can be applied to this connection ? hint: Dobtain Pue based on weld strength (transverse) BM strength = where tbm = thickness of the thinner connected plate Lw= length of the weld Fillet weld this side only i.e. lw= 9 in کہ ۔ Ри opy