1N2 + 3H2 -----> 2NH3 Diatomic nitrogen has a triple bond. (946) Diatomic hydrogen hs a single bond. (436) The three bonds in ammonia are single bonds. (390) The bond energies are given. Determine the formula to find the heat of reaction.  a. (1)(+946) + (3)(+436)+(2)(-390) b. (3)(+946) + (3)(+436)+(3)(-390) c. (1)(-946) + (3)(-436)+(2)(+390) d. (1)(-946) + (1)(-436)+(3)(+390) e. (3)(-946) + (3)(-436)+(3)(+390)

A scientist measures the standard enthalpy change for this reaction to be 296.0 kJ/mol: H₂S(g) + 2 H₂O(l) 3H₂(g) + SO₂(g) Based on this value and the standard formation enthalpies for the other substances, the standard formation enthalpy of H₂S(g) is kJ/mol. Submit Answer Retry Entire Group 1 more group attempt remaining

hello, i need help with part a, b, and c. In the chemistry lab, one often has to work with very reactive metals such as sodium and lithium. Unfortunately, these same metals can react vigorously with water or oxygen and cause fires. Given the following information:      (kJ/mol)    (kJ/mol) Li2O(s) -597.9 Li+(aq) -278.5 Na2O(s) -416 Na+(aq) -240 K2O(s) -361 K+(aq) -251 CO(g) -110.5 CO2(g) -393.5 H2O(l) -286 OH-(aq) -230 CCl4(l) -135 SiO2(s) -911 LiCl(s) -409 NaCl(s) -411 KCl(s) -436 Cl-(aq) -167   Calculate ΔH° for the following reactions:   1a)  4 Li(s) + O2(g) --> 2 Li2O(s) 1b) 2Li(s) + CO2(g) ----> Li2O(s) + CO(g) 1c) 2Li(s) + 2H2O(l) ---> 2LiOH(aq) + H2(g)

There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In the first step, calcium carbide (CaC,) and water react to form acetylene (C,H,) and calcium hydroxide: CaC, (s) + 2H,0(g) - C,H,(g) + Ca(OH), (s) In the second step, acetylene (C,H,), carbon dioxide and water react to form acrylic acid (CH,CHCO,H): 6C,H, (g) 3co,(g) + 4H,0(g) 5 CH, CHCO,H (g) Suppose the yield of the first step is 68.% and the yield of the second step is 66.%. Calculate the mass of calcium carbide required to make 10.0 kg of acrylic acid. Be sure your answer has a unit symbol, if needed, and is rounded to the correct number of significant digits.