what is f and g ?what is g and f ?l = .5 finger widthx = Arm lengthg = eye level heightd = object distaceA = angle from eye level to top of the objectf = object height from eye levelh = diameter of the sun.0127 m .7112 m 1.49668x 10^11 m1.023 degrees 2.673 x 10^9 m d. Diameter of the SunI hdStanding on the beach at sunset, you extend the tip of your finger at your full arm length fromyour face, covering the Sun. Upon moving your finger around, you find that only about half of itswidth is needed to completely cover the Sun's diameter. You measure your finger width to be 0.5inches. You know your arm length to be 28.0 inches You have be told that the Sun isapproximately 93 million miles away. Use this information to determine the approximatediameter of the Sun, filling in the table below with the proper quantities measure in meters.1=½ fingerwidthX Armlengthg = eye level d = objectheightA = anglefrom eyef= objectheight fromh= Diameterof the Sun%3D%3Ddistance93x10 mi level to top of eye levelobjectOR 1.0230127m

To find: The eye level height g, object height from eye level f, and the diameter of the sun. Given:…

Answered: d. Diameter of the Sun d. Standing on…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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what is f and g ?

what is g and f ?

l = .5 finger width	x = Arm length	g = eye level height	d = object distace	A = angle from eye level to top of the object	f = object height from eye level	h = diameter of the sun
.0127 m	.7112 m		1.49668x 10^11 m	1.023 degrees		2.673 x 10^9 m

d. Diameter of the Sun
I h
d
Standing on the beach at sunset, you extend the tip of your finger at your full arm length from
your face, covering the Sun. Upon moving your finger around, you find that only about half of its
width is needed to completely cover the Sun's diameter. You measure your finger width to be 0.5
inches. You know your arm length to be 28.0 inches You have be told that the Sun is
approximately 93 million miles away. Use this information to determine the approximate
diameter of the Sun, filling in the table below with the proper quantities measure in meters.
1=½ finger
width
X Arm
length
g = eye level d = object
height
A = angle
from eye
f= object
height from
h= Diameter
of the Sun
%3D
%3D
distance
93x10 mi level to top of eye level
object
OR 1.023
0127m

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