187 families have health insurance out of a random sample of 292 families. Kaiser states that the proportion of families who have health insurance is 63%. Can it be concluded that the proportion of families who have health insurance is greater than 63% based on a-level of 0.04?

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.6: Variation
Problem 2E
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187 families have health insurance out of a random sample of 292 families. Kaiser states that the proportion of families who have health insurance is 63%. Can it be concluded that the proportion of families who have health insurance is greater than 63% based on a-level of 0.04?
c) To find our Critical Value(s) (CV), will we use invNorm(), invT()?
invNorm()
d) Please explain the reason for the correct answer for step c.
This is a hypotheses test for population proportion (p).
Round to Two Decimal Places
CV =-1.75
Enter an integer or decimal number [more..]
f) What formula will we use for the test value?
Oz
(ã1 – 52) – (41 – 42)
Ot=
+
ni
n2
(ê1 – P2) – (pi – p2)
Oz =
p – p
O z =
V n
Ot=
Transcribed Image Text:c) To find our Critical Value(s) (CV), will we use invNorm(), invT()? invNorm() d) Please explain the reason for the correct answer for step c. This is a hypotheses test for population proportion (p). Round to Two Decimal Places CV =-1.75 Enter an integer or decimal number [more..] f) What formula will we use for the test value? Oz (ã1 – 52) – (41 – 42) Ot= + ni n2 (ê1 – P2) – (pi – p2) Oz = p – p O z = V n Ot=
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