18. An electron accelerates from rest through an electric field and into a magnetic field as shown in the diagram below. The plates have a potential difference of 85 V and are separated by 8.5 cm. The magnetic field has a magnitude of 0.75 T directed out of the page. +ve -ve electron a) What is the strength of the electric field between the plates? (1000 N/C) b) Show that the initial speed of the electron upon entering the magnetic field is 5.5 x 10ʻm/s. c) Calculate the magnitude and direction of the magnetic force on the electron. (6.6 x 10-13 N [toward the top of the page]) d) Calculate the radius of the electron's circular path. (4.1 x 10-5 m) e) If the voltage was reversed in order to accelerate a proton through the electric field and into the magnetic

Kinetic energy KE (Chapter 5) has dimensions kgm2/s2. It can be written in terms of the momentum p (Chapter 6) and mass m as KE = p2/2m (a) Determine the proper units for momentum (p) using dimensional analysis. (b) Refer to Problem 2. Given the units of force, write a simple equation relating a constant force F exerted on an object, an interval of time t during which the force is applied, and the resulting momentum of the object, p.

I am stumped on this problem. How would i start this?

Each measurement we take has a level of uncertainty in it. The smaller the uncertainty, the larger the precision our measurement has. Let's revisit how one might go about estimating the uncertainty in a measurement. If we assume our instrument is properly calibrated and we are not introducing systematic error through improper techniques, then if we take enough measurements, the average of these measurements will be around the true value. The upper and lower bounds of these measurements would then give us one method for determining our measuring device's uncertainty. (This of course is only true for a large set of measurements, but the approximation is good enough for now to get us started). For example, say we perform last week's experiment of pulling a block at a constant velocity with a force sensor across another rough surface. We take the following five measurements: F, = {2.51 N, 2.53 N, 2.50 N, 2.54 N, 2.49 N} The average of this dataset is F, = 2.51 N Now we have the choice of…

Is there any simpler solution to this? Without having to calculate so many variables?

Trying to convert 1.40mi into kilometers but still havent quite mastered the unit conversion. I tried 1.40mi * (1.609km/1mi) but thats not correct. Please assist me with this

Preliminary Basic Calculations: The speed of sound is fast, but clearly not as great as the speed of light. There is a common observation that you can tell how far away a bolt of lighting is by counting the time in seconds between the flash (which arrives almost instantaneously) and the thunder. Each second of delay means the strike is 1/5 of a mile away. This implies that sound travels about 1/5 mile/sec or (5280/5) ft/sec≈ 1000 ft/sec. THE TIR (A) What is the approximate speed of sound in meters/sec? daca).sdut llod sdt mi is sd dguonit brs trigit (sbunito ngcourts fel bas fal asqo Page 1 of 10

It's showing that b is not correct. Thank you for your help with this practice problem.

In the answer, it gives a formula f-ff=m(0) and afterwards simplies into 120 - ff = 0 and further into ff=120N. My question is how do you not have to divide by 0 to finish the equation if that makes sense. To simply further why are we able to ignore the m(0) portion?

These are basic physics questions that I need help understanding for homework. Thank you for your help and expertise!