16. The proton NMR spectrum is shown for a compound with formula C3H9NO4. The infrared spectrum displays strong bands at 1750 and 1562 cm- and a medium intensity band at 1320 cm-. The normal carbon-13 and the DEPT experimental results are tabulated. Draw the struc- ture of this compound. Normal Carbon DEPT-135 DEPT-90 14 ppm Positive No peak No peak 16 Positive 63 Negative No peak 83 Positive Positive 165 No peak No peak

Shown are the H NMR spectra for 2 isomeric compounds three and four of the formula C5H10O. The IR spectrum of both have an absorption in the region of 1700 to 1730 cm-1. Provide the structure for each compound, and which hydrogen atoms give rise to the peaks in each spectrum. The peak at 7.27 ppm can be ignored, and the red numbers are integration values.

I need help drawing the structure of the chemical formula given based on the NMF spectrum.

2) Figures 2 to 4 show the IR, 1H NMR and 13C NMR spectra of a compound with formula C3H5N 2a) Identify bands A and B in the IR spectrum 2b) Using the information from the 1H NMR spectrum, fill in the table below Peak cluster (ppm) Multiplicity Number of H in neighbouring C Proposed identification 0       1.30         2.35       2c) Propose a structure for the compound C3H5N. Justify your answer by referring to key spectral features of the 3 spectra.

Determine the following for the compound C6H15N a.) degrees of unsaturation  b.) Assign the principal IR absorption bands above 1500 c.) draw the structure of the compound  d.) label the protons on your structure with letters and assign them to peaks on the NMR spectrum.

Do not give handwriting solution.

Can i get step by step help with this problem step by step please

The NMR spectra for compound 1 were acquired in a 7.5 mg / 0.6 mL solution ofCDCl3 and are found in the accompanying file. The 1H are also listedbelow. Identify the name of compound 1 and Provide a full analysis of the NMR spectra for compound 1 with table showing peak name and assignment  1H NMR (400 MHz, CDCl3) δ 7.73 (d, J = 9.5 Hz, 1H), 7.56 (ddd, J = 8.5, 7.5, 1.6 Hz, 1H),7.51 (dd, J = 7.5, 1.6 Hz, 1H), 7.36 (d, J = 8.5 Hz, 1H), 7.30 (dd, J = 8.5, 7.5 Hz, 1H), 6.45(d, J = 9.5 Hz, 1H).

shows five isomers of C5H10O2. The two structures that would be hardest to distinguish by IR spectroscopy are

The IR spectrum below is consistent with which molecule? Transmitance 0.8 0.6 0.4 0.2 0.0 A B D 3000 A INFRARED SPECTRUM Wavenumber (cm-1) OH 2000 B CH 3 1000 OH D