14-Two wires have the same length and the same resistance. One is made from aluminum and the other from copper. Obtain the ratio of the cross-sectional area of the aluminum wire to that of the copper wire (PAI=2.63x10 2.m, pCu=1.72x10* 2.m). 1

Determine the elongation of an aluminium hollow cylinder of an inner diameter of 1.1 cm & the external diameter of 22.7 mm is subjected to an elastic tensile load of 271 kN. Take the elastic modulus of the aluminum specimen as 73 GPa and the initial length of the hollow cylinder as 186 mm. Solution: i) Cross-sectional Area (in mm2) =  ii) Stress-induced (in N/mm2) =  iii) Strain-induced (at least 3 decimal places accuracy)=  iv) Elongation (in mm) =

An aluminum alloy [E = 72 GPa; ν = 0.33; α = 23.0 × 10–6/°C] plate is subjected to a tensile load P. The plate has a depth of d = 255 mm, a cross-sectional area of A = 6500 mm2, and a length of L = 4.6 m.  The initial longitudinal normal strain in the plate is zero. After load P is applied and the temperature of the plate has been increased by ΔT = 68°C, the longitudinal normal strain in the plate is found to be 2570 με.  Determine: (a) the magnitude of load P. (b) the change in plate depth Δd.

A specimen of magnesium having a rectan- gular cross section of dimensions 3.2 mm × 19.1 mm (in. × in.) is deformed in ten- sion. Using the load-elongation data tabulated as follows, complete parts (a) through (f). lbf 0 310 625 1265 1670 1830 2220 2890 3170 3225 3110 2810 Load N 0 1380 2780 5630 7430 8140 9870 12,850 14,100 14,340 13,830 12,500 in. 2.500 2.501 2.502 2.505 2.508 2.510 2.525 2.575 2.625 2.675 2.725 2.775 Fracture Length mm 63.50 63.53 63.56 63.62 63.70 63.75 64.14 65.41 66.68 67.95 69.22 70.49 (a) Plot the data as engineering stress versus engineering strain. (b) Compute the modulus of elasticity. (c) Determine the yield strength at a strain offset of 0.002. (d) Determine the tensile strength of this alloy. (e) Compute the modulus of resilience. (f) What is the ductility, in percent elongation?

Consider a material with the stress-strain diagram shown where the yield point is 400 MPa (similar to a generic metal, but approximated to make the calculations easier). The material is stressed to 900 MPa. What is the change in the modulus of resilience? 1200- 800 σ (MPa) 400 a more realistic curve 0.10 0.20 0.30 0.40 ε

A 30-cm-long cylindrical rod of red brass (E = 120 GPa) is loaded axially causing the rod to elongate 0.580 mm. If the diameter of the rod is 1.75 cm, what is the load?

A spherical pressure vessel has an inside diameter of 4 m and a wall thickness of 15 mm. The vessel will be constructed from structural steel [E = 200 GPa; v = 0.29] that has a yield strength of 203 MPa. If the internal pressure in the vessel is 1930 kPa, determine the factor of safety with respect to the yield strength. 1.58 2.21 O 1.30 1.45 O 1.13

2. An aluminum alloy (E = 75 GPa) tube A is used to support a 30 mm diameter steel (E 210 GPa) rod B, as shown below. Determine the minimum cross-sectional area required for the tube if the maximum defection of the loaded end of the rod must be limited to 0.3 mm. 300 mm 750 mm 65 AN

Rigid bar ABC is supported by two aluminum alloy (E = 10,000 ksi) rods as shown below. The horizontal distance between rods (1) and (2) is a = 150 in. Rod (1) has a length of L₁ = 99 in. and a cross-sectional area of A₁ = 0.55 in.². Rod (2) has a length of L₂ = 96 in. and a cross-sectional area of A₂ = 0.95 in.². Rigid bar ABC is to remain horizontal under a load of P = 35 kips. Determine the distance x from joint A to the location of load P so that bar ABC remains horizontal. L Answer: X= i (1) eTextbook and Media Save for Later x in. B (2) L2 Attempts: 0 of 5 used Submit Answer

Help me