13. Which one of the following represents the transition state of the rate-determining step of the reaction shown below between tert-butyl bromide and methanol in which isobutylene is formed? The reaction takes place with an E1 mechanism. The overall reaction is- H3C H3C CH3 H3C CH3 Omm Θό -Br Ꮎ -Br H A CH3 H3C B H3C H3C SOOH-CH2 CH3 SOHCH2CH H -Br H (CH3)3C-Br (CH3)2C=CH2 + HBr с D CH3OH CH3 CH3

Consider the following reaction mechanism. Step 1: 2X + Y- W + 2 Z fast Step 2: Z- U+ V slow Step 3: V+Z-2 W + Y fast The rate-limiting step is Step because. 1; the first step must occur before any others can occur O 2; it uses a product of the first step O 3; the last step is always the rate-limiting step O 2; it is the slowest step

Identify the transition state for the reaction between tert-butyl chloride and sodium hydroxide. H H-c-H 8- 8- HO---- C- CI H3C CH3 H 8- Но- -H----c-H 8- HạC-C- ČH3 -CI H-c-H 8+ 8+ HO---- CI H3C CH3 H. &+ HO-----H----C 8+ H3C-C----CI ČH3 %3

3. The following three SNAR transformations follow different mechanisms. Draw an intermediate or transition state for each reaction that relates the correct mechanism. Write a short sentence as to why that is the correct intermediate for the reaction. Reaction 1: Reaction 2: NO2 NO2 NO₂ + NaOMe NO2 + NaOH2 1. aq NaHCO3. 100 C 2. H₂O+ OMe NO2 NO₂ OH ŇO₂ NO2 Reaction 3: CFa Br CF3 8--2 + NaNH2 NH3 NH₂ Intermediate/transition state Intermediate/transition state Intermediate/transition state

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1d.

Below is the equation for a nucleophilic substitution reaction and some experimental data. CH3CH2Br + CH3COO- ⇌ CH3CH2CO2CH3 + Br- ΔH=-75 kJ/mol Rate = k [CH3CH2Br][CH3COO-] Which reaction energy profile would be the best representative of the data provided?

Which of the species below best depicts the likely transition state for the reaction between methyl iodide, CH3I and sodium methylthiolate, NaSCH3?

Please draw the detailed mechanism of this below reaction scheme in 2 steps. Please draw it carefully, I don't understand, for example, why in the first step, the C = O is replaced by C = N and in the second step, the 2 double bonds can react with each other.