120 mm diameter siphon draws water from the reservoir. Considering that the elevation differences, hị and h, are2.8 m and 5.2 m respectively, determine the; a. Discharge ofthe water flowing through the siphon *(m³/s), Absolute pressure at Point B *(kPa). Draw the EL and HGL for a given system. Ns? Pwater = 1000 m4 kN Patm = 101,3 m2 Please Draw

= Water flows into a tank and out through another pipe, as shown in the figure below. The water in the tank has a surface area, Asur f 5.6 m². At the bottom of the tank there is a door inclined at an angle = 25 degrees with respect to the horizontal. The door has a length L = 1.1 m and a width w=1 m (out of the page). The flowrate into the tank is Q₁ (t) flowrate out is Qo(t) = 0.05 m³/s At time t = Asurf = 0.26 m³/s and the 0, the water has a depth ho = 2.5 m. The density of water is p = 1000 kg/m³. Ө h(t) Qout

Water flows over a dam into a rectangular channel of width b (out of page). At the bottom of the dam, the depth of flow is h₁. As you may have seen on watching rapid channel flow, the water may suddenly change elevation to height h₂ as it passes through a highly disturbed region called the hydraulic jump. If velocity is assumed uniform at 1 and 2, compute the height h2 using the control volume analysis. Take the pressures at 1 and 2 as hydrostatic, and assume that the flow is steady. Neglect friction at the channel bed and walls. (Courtesy of the Wright Water Engineers, Inc. and ASDSO) Hydraulic jump h₁ = 3 ft V₁ = 25 ft/s BE 2 h₂ =? V₂ = ? (a) Find the cubic equation, in terms of h₁, V₁, and g, that you must solve for the downstream depth h₂ of the water channel. (b) For h₁ = 3 ft and V₁ = 25 ft/s, find the downstream depth h₂. Use the standard value for g. Note that you are solving a cubic equation, and only one of the solutions is correct.

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