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12 - Aşağıda verilen fonksiyonun türevi aşağıdakilerden hangisine eşittir? 2 h(x) = r(-x) – r(-x– 2) – u(-x – 2) +r(x) –r(x – 3) – 2u(x – 3) -u(-x) + u(-x – 2) + 8(-x – 2) +u(x)-u(x - 3) + 28(x – 3) 2 b) O -u(-x) + u(-x - 2) + 8(-x – 2) +u(*) -u(x – 3) – 26(x - 3) -u(-x) + u(-x – 2) + 8(-x – 2) –u(x) -u(x- 3) – 28(x – 3) c) o)0 -u(-x) + u(-x – 2) + 8(-x – 2) +u(x – 1) –u(x- -u(x – 3) – 26(x – 3) 2 -u(-x) – u(-x – 2) + 8(-x – 2) +u(x) –u(x – 3) – 28(x – 3) e)

12 - Aşağıda verilen fonksiyonun türevi aşağıdakilerden hangisine eşittir? 2 h(x) = r(-x) – r(-x– 2) – u(-x – 2) +r(x) –r(x – 3) – 2u(x – 3) -u(-x) + u(-x – 2) + 8(-x – 2) +u(x)-u(x - 3) + 28(x – 3) 2 b) O -u(-x) + u(-x - 2) + 8(-x – 2) +u(*) -u(x – 3) – 26(x - 3) -u(-x) + u(-x – 2) + 8(-x – 2) –u(x) -u(x- 3) – 28(x – 3) c) o)0 -u(-x) + u(-x – 2) + 8(-x – 2) +u(x – 1) –u(x- -u(x – 3) – 26(x – 3) 2 -u(-x) – u(-x – 2) + 8(-x – 2) +u(x) –u(x – 3) – 28(x – 3) e)

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Circuit analysis 2

Which of the following is the derivative of the function given below equal to?

 

12 - Aşağıda verilen fonksiyonun türevi aşağıdakilerden hangisine eşittir? 2 h(x) = r(-x) – r(-x – 2) – u(-x – 2) +r(x) –r(x – 3) – 2u(x – 3) a) O -u(-x) + u(-x– 2) + 8(-x – 2) +u(x) -u(x - 3) + 26(x – 3) 2 2 b) O -u(-x) + u(-x – 2) + 8(-x – 2) +u(x) -u(x – 3) – 26(x – 3) -u(-x) + u(-x – 2) + 8(-x – 2) –u(x) – u(x – 3) – 28(x – 3) c) o)0 -u(-x) + u(-x – 2) + 8(-x – 2) +u(x – 1) –u(x- x – 2) +u(x – 1) -žu(x – 3) – 26(x – 3) 2 -u(-x) – u(-x – 2) + 8(-x – 2) +u(x) –u(x – 3) – 28(x – 3) e)
Transcribed Image Text:12 - Aşağıda verilen fonksiyonun türevi aşağıdakilerden hangisine eşittir? 2 h(x) = r(-x) – r(-x – 2) – u(-x – 2) +r(x) –r(x – 3) – 2u(x – 3) a) O -u(-x) + u(-x– 2) + 8(-x – 2) +u(x) -u(x - 3) + 26(x – 3) 2 2 b) O -u(-x) + u(-x – 2) + 8(-x – 2) +u(x) -u(x – 3) – 26(x – 3) -u(-x) + u(-x – 2) + 8(-x – 2) –u(x) – u(x – 3) – 28(x – 3) c) o)0 -u(-x) + u(-x – 2) + 8(-x – 2) +u(x – 1) –u(x- x – 2) +u(x – 1) -žu(x – 3) – 26(x – 3) 2 -u(-x) – u(-x – 2) + 8(-x – 2) +u(x) –u(x – 3) – 28(x – 3) e)
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