10. What is the expected product of this reaction? To answer, consider the intermediate(s) that can form? Show the mechanism of the reaction. O₂N. LICI HjC-ONa NO 1 molar equivalent

Is there a reason those sig figs are wrong or are my calculations just completely off?

Calculate (triangle)G for: C2H4 (g) + H2O (g) -> C2H5OH(g)

Which of the following gases consist of molecules containing four or more atoms? Rn O NO O CO Ar Kr CO2 Хе H,S HF H, F, N, sO, Ne HCN Cl, NO, CH, Не Sa HCI MacBook Pro

Rb₂O(s) +____H₂O(1)→ Co2(CO3)3(s) + heat → 3_H₂O(1) + 1_As2O5(s) →➜ NaClO3(s) + heat → (110q000 sd, opt! 2 H3 As 0, 4 Ini Siyoda canl Mg(s) + H₂SO4(aq) → Myson noileupo unor ton boonstad to out + H₂ Om adami zogasdo ne

(4d-202) A buffer solution is made by mixing H3PO4 and NaH2PO4 in water. How does this buffer system neutralize an addition of 5 mL of 0.45 M NaOH? Choose one of the options below. • The H3PO4, as a weak acid, will neutralize the added NaOH • The NaH2PO4, as a weak base, will neutralize the added NaOH • The H3PO4, as a weak base, will neutralize the added NaOH • The NaH2PO4, as a weak acid, will neutralize the added NaOH For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac). Paragraph Arial 14px A v Ix Q x² X, g ST 田用国 EXE ABC Ť {;} +) P. O WORDS POWERED BY TINY +]

Please don't providehandwritten solution ....

A A BUDE А F D CI AICI 3 Br Zn(Hg) + HCl(aq) NBS, light OH (aq) heat B E Br C F ? Br

ORT SHEET Heat of Neutralization EXPERIMENT elemsboomfchg lom 12 A. Heat Capacity of Calorimeter 1. Temp. of calorimeter and water before mixing 2. Temp. of warm water °C 22.0 39,0 30.3 3. Maximum temp. determined from your curve °C 4. Heat lost by warm water (temp decrease x °C 50.0 g x 4.184 J/K-g) = 02), 5. Heat gained by cooler water (temp. increase x 50.0 g x 4.184 J/K-g) = 30,3 22.0)x 13626J s0.0gmpi S0.0gy 6. Heat gained by the calorimeter [(4) – (5)] = 7. Heat capacity of calorimeter: heat gained by the calorimeter temperature increase J/K 3. Heat of Neutralization of HCl-NaOH 22.2 22.2. °C . Temp. of calorimeter and NaOH Temp. of HCI AT determined from your curve after adding HC1 °C to the NaOH Heat gained by solution (temperature increase x ON 100 g x 4.184 J/K-g) = 9977.8J %3D Heat gained by calorimeter (temperature increase x heat capacity of calorimeter) = J %3D Total joules released by reaction [(3) + (4)] = Tight O 2018 Pearson Education, Inc.

Is 10b more than one product? Not sure the way it is written.