10. Two previously undeformed specimens of the same metal are to be plastically deformedby reducing their cross-sectional areas. One has a circular cross section, and the other isrectangular; during deformation the circular cross section is to remain circular, and therectangular is to remain as such. Their original and deformed dimensions are as follows:Original dimensionsDeformed dimensionsCircular(diameter, mm)15.412.1Rectangular(mm)129 x 17575 x 164Which of these specimens will be the hardest after plastic deformation?

Determining Specimen Hardness After Plastic Deformation Problem Statement: We have two specimens,…

Answered: 10. Two previously undeformed specimens…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Solve the following problems and SHOW YOUR COMPLETE SOLUTIONS FOR BETTER UNDERSTANDING
show the work by steps. only HANDWRITTEN answer needed ( NOT TYPED)
Question-8. . A cylindrical metal specimen with a diameter of 16 mm and length of 88 mm is to be subjected to a tensile stress of 80 MPa; at this stress the resulting deformation is elastic. (a) If the elongation is less than 0.058 mm, which of the metals in the table can be considered as candidates? Why ? (b) If the maximum permissible diameter decrease is 0.0012 mm when the tensile stress of 68 MPa is applied, which of the metals satisfy the criterion in question (a) are the suitable candidates? Why ? Metal Shear Modulus / GPa Modulus of Elasticity / GPa 69 Poisson's Ratio Al 25 0.33 Cu 110 46 0.34 Mg 45 17 0.29 Ni 207 76 0.31 Ti 107 6.5 0.34 W 407 23.2 0.28
The following data are obtained from a tensile test of a copper specimen. - The load at the yield point is 148 kN. - Length of the specimen is 26 mm. - The yield strength is 83 kN/mm². - The percentage of elongation is 49 %. Determine the following (i) Diameter of the specimen, ii) Final length of the specimen, iii) Stress under an elastic load of 13 kN, iv) Young's Modulus if the elongation is 2.9 mm at 13 kN and (v) Final diameter if the percentage of reduction in area is 22 %. Young's Modulus of the Specimen (in N/mm?) Final Area of the Specimen at Fracture (in mm) 1. Final Diameter of the Specimen after Fracture (in mm)
10. A standard steel specimen of 0.504" diameter elongated 0.0125" in an 8" gage length during a test where it was subjected to a tensile force of 6249 lb. If the specimen's gage length was measured to be 8.0025" after the test was over, what was the permanent plastic deformation? What is the elastic deformation and what is the modulus of elasticity of that metal? r PL AE
Determine the indentation diameter and the surface area of indentation of a copper material subjected to a Brinell hardness test with a test force of 7.3 kN using a hardened steel ball indentor of 11 mm. Take the Brinell Hardness Number as 948. Solution: i) Indentation Diameter (in mm) = ii) Surface Area of Indentation (in mm2) =
I want the solution clearly
At operating stress of 420MPa, the number of cycles to fail a specimen is 65 cycles. At operating stress of 360MPa, the number of cycles to fail the specimen is 390 cycles, and at operating stress of 130MPa, the number of cycles to fail the specimen is 11,900 cycles. A test sequence as follows is designed: first, operating stress of 420MPa for 7 cycles, second, operating stress of 360MPa for 65 cycles, and third, operating stress of 130MPa for 325 cycles. Determine at what number of cycle and which operating stress level the specimen would be expected to fail if the above sequence is repeated.
I want to solve the required squares and their units of measurement in regularity, please
If the true stress is 74 MPa for the specimen described above elongated by 2.6 cm, what is the difference between nominal and true stress in MPa (absolute value)?

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