Use a two-tailed test with α = .05 to determine whether these data are sufficient to conclude that high-creativity people are more likely to cheat than people with lower levels of creativity.  B) Compute Cohen's d to measure the size of the effect. C) Write a sentence demonstrating how the results from the hypothesis test and the measure of effect size would appear in a research report.

Identifying individuals with a high risk of Alzheimer's disease usually involves a long series of cognitive tests. However, researchers have developed a 7-Minute Screen, which is a quick and easy way to accomplish the same goal. The question is whether the 7-Minute Screen is as effective as the complete series of tests. To address this question, Ijuin et al. (2008) administered both tests to a group of patients and compared the results. The following data represent results similar to those obtained in the study.    7-Minute Screen Cognitive Series 3 11 8 19 10 22 8 20 4 14 7 13 4 9 5 20 14 25 Which statistical test would you select: Answer    H0: Answer H1: Answer What is the coefficient that indicates the strength of the relationship? Answer =Answer What is the standard error? Answer What is the appropriate 95% CI?  [ Answer , Answer ] What is the d-effect size? Answer What is the t-observed? Answer What is the actual p-value? Answer THREE decimal places…

Does the test result Provide sufficient evidence that light alcohol consumption has a negative impact on the driving performance of a sleep deprived driver. Why or why not

Select all that apply:   We should reject H0.   We should not reject H0.   At the 1% significance level, the data do not provide sufficient evidence to conclude that the amount of time American teenagers watch television per week is different from 14.1 hours.   At the 1% significance level, the data provide sufficient evidence to conclude that the amount of time American teenagers watch television per week is different from 14.1 hours.

Identifying individuals with a high risk of Alzheimer’s disease usually involves a long series of cognitive tests. However, researchers have developed a 7-Minute Screen, which is a quick and easy way to accomplish the same goal. The question is whether the 7-Minute Screen is as effective as the complete series of tests. To address this question, Ijuin et al. (2008) administered both tests to a group of patients and compared the results. The following data represent results similar to those obtained in the study. Patient 7-Minute Screen Cognitive Series A 3 7 B 7 15 C 4 14 D 5 13 E 7 9 F 5 15 G 11 25 The alternative hypothesis in words and null hypothesis in symbols for a two-tailed test is

Nutritional researchers conducted an investigation of two high-fiber diets intended to reduce cholesterol level. a group of people with high cholesterol were randomly selected to receive an "rice" diet or a "vegetable" diet for 20 days. Use a t-test to compare the diets at 5% significance level. Null Hypothesis: The means from two respective diets are the same Alternative Hypothesis:  The means from the two diets differ.   Fall in Cholesterol (mg/dL) Diet     n       Mean     SD   Rice 10   14.4 6.8 Vegetable 9   10.57 6.37 do we fail to reject the null hypothesis or reject null hypothesis

Two professors at a local college developed a new teaching curriculum designed to increase students' grades in math classes. In a typical developmental math course, 55% of the students complete the course with a letter grade of A, B, or C. In the experimental course, of the 15 students enrolled, 11 completed the course with a letter grade of A, B, or C. Is the experimental course effective at the a = 0.1 level of significance? Complete parts (a) through (g). Is there sufficient evidence to support the research that the experimental course is effective? A. No, reject the null hypothesis because the P-value is less than a. There is insufficient evidence to conclude that the experimental course is effective. B. Yes, reject the null hypothesis because the P-value is less than a. There is sufficient evidence to conclude that the experimental course is effective. CC. No, do not reject the null hypothesis because the P-value is greater than a. There is insufficient evidence to conclude that…

Identifying individuals with a high risk of Alzheimer’s disease usually involves a long series of cognitive tests. However, researchers have developed a 7-Minute Screen, which is a quick and easy way to accomplish the same goal. The question is whether the 7-Minute Screen is as effective as the complete series of tests. To address this question, Ijuin et al. (2008) administered both tests to a group of patients and compared the results. The following data represent results similar to those obtained in the study:   Patient            7-Minute         Screen Cognitive Tests  A                            3                           11  B                            8                           19  C                          10                           22  D                            8                          20  E                            4                           14  F                            7                           13  G                           4…