10 8 6 PPM 2 2 N 0

PLS ANSWER ONLY THE CIRCLED ONE! I just need the answer. Not a long paragraph. Just answer.

8. Sketch the off-resonance-decoupled 1³C spectra of the following compound. H H C C-H H The splitting pattern of off-resonance decoupled spectrum indicates the number of protons attached to the carbon. 13C nuclei are split only by the protons attached directly to them. The N + 1 rule applies: a carbon with N number of protons gives a signal with N + 1 peaks (e.g. carbon atom with one proton appears as a doublet; carbon with two attached protons gives a triplet etc.) • Carbon atoms with more hydrogens absorb more strongly.

The HNMR spectra shown below contains six singlets that correspond to the six different proton groups identified in structure 1. Use an HNMR table to help match each signal to a proton group.

Assign all of the signals in the ¹H NMR spectrum for propyl acetate. Fill in the table below with the 'H NMR data. Number each proton (or set of protons) to match the corresponding peak in the NMR. Integration Splitting Propyl acetate structure with protons labeled Signal - Chemical shift (ppm) 1 2 3 4 11 propyl acetate 10 9 8 7 6 5 ppm 2H, triplet 4 3 3H, singlet 3H, triplet 2H, sextet 2 1 Figure 3.7 ¹H NMR spectrum for propyl acetate. 0

please draw the molecule and label it based on the data in the sheet and use the label in the data table.

Explanation/Answer cannot be hand-drawn! Must be typed or illustrated digitally

Propose a structure that is consistent with the following 1H NMR spectra. In each case, the molecular formula is provided. For spectra with numbers at the bottom of the signal you will need to determine the integration, others with numbers above the signal integration has been determined for you.

Can you explain this nmr