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(10-13) Solve the system of equations by Jacobi's iteration method at fourth iteration. 20X1 + X₂-2X₁-17 3X₁ + 20X2-X₁=-18 2X1-3X2+ 20X3-25 let initial guess of X1=X2-X3-0 10) in second iteration: (X₁2, X₂², X3²) = a) (1.9094, -0.9967, 0.0001) c) {1.9567,-0.89945, 0,0001) e) { 0.999966, -1.000078, 11) in fourth iteration (X₁, X₂, X;} = a) {1.9094, -0.9967, 0.0001} c) {1.9567, -0.89945, 0,0001} b) (1.00125, -1.0015, 1.00325) d) {1.0004,-1.000025, 0.9965) 0.999956} 12) solution of the system = a) {-1, 0, 1) e) { 0.999966, -1.000078, 0.999956} b) {1,-1, 1} b) (1.00125, -1.0015, 1.00325) d) {1.0004,-1.000025, 0.9965) c) {2,-1,0) d) {1,-1,-1}

(10-13) Solve the system of equations by Jacobi's iteration method at fourth iteration. 20X1 + X₂-2X₁-17 3X₁ + 20X2-X₁=-18 2X1-3X2+ 20X3-25 let initial guess of X1=X2-X3-0 10) in second iteration: (X₁2, X₂², X3²) = a) (1.9094, -0.9967, 0.0001) c) {1.9567,-0.89945, 0,0001) e) { 0.999966, -1.000078, 11) in fourth iteration (X₁, X₂, X;} = a) {1.9094, -0.9967, 0.0001} c) {1.9567, -0.89945, 0,0001} b) (1.00125, -1.0015, 1.00325) d) {1.0004,-1.000025, 0.9965) 0.999956} 12) solution of the system = a) {-1, 0, 1) e) { 0.999966, -1.000078, 0.999956} b) {1,-1, 1} b) (1.00125, -1.0015, 1.00325) d) {1.0004,-1.000025, 0.9965) c) {2,-1,0) d) {1,-1,-1}

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter9: Systems Of Equations And Inequalities
Section9.1: Systems Of Equations
Problem 6E
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(10-13) Solve the system of equations by Jacobi's iteration method at fourth iteration. 20X₁ + X₂-2X₁-17 3X₁ + 20X₂-X₁=-18 2X1-3X2+ 20X3=25 let initial guess of X1=X2-X3-0 10) in second iteration: (X₁2, X₂², X3²) = a) (1.9094, -0.9967, 0.0001) c) {1.9567, -0.89945, 0,0001) e) { 0.999966, -1.000078, 11) in fourth iteration (X₁, X₂, X34} = a) {1.9094, -0.9967, 0.0001} c) {1.9567, -0.89945, 0,0001} b) (1.00125, -1.0015, 1.00325) d) {1.0004,-1.000025, 0.9965) 0.999956} 12) solution of the system = a) {-1, 0, 1} e) { 0.999966, -1.000078, 0.999956} b) {1,-1, 1} b) (1.00125, -1.0015, 1.00325) d) {1.0004,-1.000025, 0.9965) c) {2,-1,0) d) {1,-1,-1}
Transcribed Image Text:(10-13) Solve the system of equations by Jacobi's iteration method at fourth iteration. 20X₁ + X₂-2X₁-17 3X₁ + 20X₂-X₁=-18 2X1-3X2+ 20X3=25 let initial guess of X1=X2-X3-0 10) in second iteration: (X₁2, X₂², X3²) = a) (1.9094, -0.9967, 0.0001) c) {1.9567, -0.89945, 0,0001) e) { 0.999966, -1.000078, 11) in fourth iteration (X₁, X₂, X34} = a) {1.9094, -0.9967, 0.0001} c) {1.9567, -0.89945, 0,0001} b) (1.00125, -1.0015, 1.00325) d) {1.0004,-1.000025, 0.9965) 0.999956} 12) solution of the system = a) {-1, 0, 1} e) { 0.999966, -1.000078, 0.999956} b) {1,-1, 1} b) (1.00125, -1.0015, 1.00325) d) {1.0004,-1.000025, 0.9965) c) {2,-1,0) d) {1,-1,-1}
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