Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN: 9780134463216
Author: Robert F. Blitzer
Publisher: PEARSON
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**Mathematical Problem: Solving a Quadratic Equation**

**Problem Statement:**

Solve for \( x \).

\[ R x^2 + T x + Q = 0 \]

This problem involves solving a quadratic equation in the standard form, where \( R \), \( T \), and \( Q \) are constants, and \( x \) is the variable. 

To solve this equation, you can use the quadratic formula:

\[ x = \frac{-T \pm \sqrt{T^2 - 4RQ}}{2R} \]

For real solutions, the discriminant (\( T^2 - 4RQ \)) must be non-negative. Depending on the values of the discriminant:

- If \( T^2 - 4RQ > 0 \), there are two distinct real solutions.
- If \( T^2 - 4RQ = 0 \), there is exactly one real solution (a repeated root).
- If \( T^2 - 4RQ < 0 \), there are no real solutions; instead, there are two complex solutions.

The quadratic formula and the evaluation of the discriminant provide a comprehensive method for solving any quadratic equation.
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Transcribed Image Text:**Mathematical Problem: Solving a Quadratic Equation** **Problem Statement:** Solve for \( x \). \[ R x^2 + T x + Q = 0 \] This problem involves solving a quadratic equation in the standard form, where \( R \), \( T \), and \( Q \) are constants, and \( x \) is the variable. To solve this equation, you can use the quadratic formula: \[ x = \frac{-T \pm \sqrt{T^2 - 4RQ}}{2R} \] For real solutions, the discriminant (\( T^2 - 4RQ \)) must be non-negative. Depending on the values of the discriminant: - If \( T^2 - 4RQ > 0 \), there are two distinct real solutions. - If \( T^2 - 4RQ = 0 \), there is exactly one real solution (a repeated root). - If \( T^2 - 4RQ < 0 \), there are no real solutions; instead, there are two complex solutions. The quadratic formula and the evaluation of the discriminant provide a comprehensive method for solving any quadratic equation.
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