1.Calculate the heat of formation of PCI5 (cr), given the heats of the following reactions at 25C: 2P (cr) + 3Cl2(g) = 2PCI3 (1) PCI3 (1)+ Cl2 (g) = PCI5 (cr) H = -635.13 kJ /mole H = -137.28 kJ / mole

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