1. Which of the following compounds would be soluble or insoluble? (3 pts) KCI Hg2Cl2 (NH4)2CO3 Soluble Cr(NO3)6 CaSO4 PbCl2 Insoluble 2. Predict the products and circle P if the reaction is a precipitation or NR for no reaction. (1.5 pts) Sodium carbonate and copper (II) sulfate react to form what products? P NR 3. Balance the following reaction: (1 pts) C10H22(g) + O2(l) → _CO2(aq) + H2O(g) 4. How many grams of oxygen are present in 0.245 g of potassium sorbate (KC6H7O2)? (2 pts) 5. a. Oxygen-15 is a positron emitter. Write a balanced nuclear equation for the loss of a positron. (1.5 pts) b. Oxygen-15 is a beta (negatron) emitter. Write a balanced nuclear equation for the loss of a negatron. b. Oxygen-15 is an alpha emitter. Write a balanced nuclear equation for the loss of an alpha particle.

3 Bal, (aq)+ 2 Nag POq Caq) 7 BalPO42 + l6 Nal laq • Consider the reaction of 30.0mL of 0.270M Balz with 20.0 mL of 0.3ISM Naz PO4. Lwhat quantity in meles of Balz are preset in the solution? are produced /What quantitg in moles of precipitate E ali Bal were consumed based on the balanced chomical equation? 6) What auantity in males of Na3 Pla aro present in soluction? d) What quantity in moles of precipitate are paduced if all the Naz PO, were cansumed based on the balanced chemi.cal equation? e) which reactant is limisting f What mass (in g) of precipitate is firemed when the limiting reactant is considered?

For lab 4, we combined baking soda with vinegar, according to the chemical equation NaHCO 3 + CH 3COOH ==== NaCH 3COO + CO 2 + H 2O Consider 3 experiments: (i) 2g baking soda + 5mL vinegar, (ii) 2g baking soda + 10mL vinegar and (iii) 2g baking soda + 20mL vinegar. The amount of CO 2 produced was highest for (iii) and lowest for (i). For these experiments, which of the following is true? Vinegar ran out first Baking soda ran out first They both ran out at the same time Neither ran out

Average the two percentages and calculate the percentage difference. given : Concentration of acetic acid in the 100 mL sample of titration 1 = 3.238 % Concentration of acetic acid in the 100 mL sample of titration 2 = 3.099 % NaOH vs CH3COOH Burette solution is NaOH and the pipette solution is 5.0 mL of Vinegar Titration Initial burette reading Final burette reading Volume of NaOH consumed Average volume of NaOH Approximate  0.0 mL 20.1 mL 20.1 mL 20.3 mL Titration 1 0.0 mL 20.9 mL 20.9 mL Titration 2 0.0 mL 20.0 mL 20.0 mL To find the average volume  Average volume = 20.1 mL + 20.9 mL + 20.0 mL320.1 mL + 20.9 mL + 20.0 mL3                            = 20.3 mL Concentration of Vinegar = Volume of NaOH * Concentration of NaOHVolume of vinegarVolume of NaOH * Concentration of NaOHVolume of vinegar                                           = 20.3 mL * 0.0647 M5.0 mL20.3 mL * 0.0647 M5.0 mL                                           = 0.2627 M Concentration of NaOH = Volume of…

Below you will find five reaction products (labeled product 1, product 2, etc.), but you will only find four reaction schemes. Your job is to match the reaction scheme with the correct product. Simply fill in the blank with the product number (i.e. 1,2,3,4, or 5). Then, state the regio-control that governs the reaction (i.e. Markovnikov or anti-Markovnikov). If the reaction does not have any regio-control then enter none. OH X Product 1 iocontrol: Product 2 1. Hg(OAc)2, H₂O 2. NaBH4 $ -OH do % Product 3 OH to 4- Product 4 OH OH Product 5 700 hp

I keep getting wring answers even when I plug in the equation exactly. Can you help me figure out what I'm doing wrong?

K14.

Based on the associated solubility chart, at what temperature would you need to heat a solution of KCI to dissolve 80.0 g of NaNO3 in 100.0 g of H2O? Solubility Chart 100 90 NANO 80 70 60 CaCl 50 Pb(NO)2 40 NaCI KCI 30 20 KCIO, 10 Ce,(SO) 10 20 30 40 50 60 70 80 90 100 Temperature (°C) OCT 26 tv Solubility (g of salt in 100 g H,0) SONY

PbCrO4 is a common pigment called chrome yellow (or school bus yellow).  It has a solubility of 1.71 x 10-4  g/L. The solubility product of PbCrO4, Ksp = ________.  Enter the result in scientific notation to 1 decimal.  e.g. enter 5.6x10-5 as 5.6E-5.

KNO3 at 60oC