1. Which of the following compounds would be soluble or insoluble? (3 pts)KCIHg2Cl2(NH4)2CO3SolubleCr(NO3)6CaSO4PbCl2Insoluble2. Predict the products and circle P if the reaction is a precipitation or NR for no reaction.(1.5 pts)Sodium carbonate and copper (II) sulfate react to form what products?PNR3. Balance the following reaction: (1 pts)C10H22(g) +O2(l) →_CO2(aq) +H2O(g)4. How many grams of oxygen are present in 0.245 g of potassium sorbate (KC6H7O2)? (2pts)5. a. Oxygen-15 is a positron emitter. Write a balanced nuclear equation for the loss of apositron. (1.5 pts)b. Oxygen-15 is a beta (negatron) emitter. Write a balanced nuclear equation for the loss ofa negatron.b. Oxygen-15 is an alpha emitter. Write a balanced nuclear equation for the loss of an alphaparticle.

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Answered: 1. Which of the following compounds…

Chemistry & Chemical Reactivity

10th Edition

ISBN:9781337399074

Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Chapter20: Environmental Chemistry-earth's Environment, Energy, And Sustainability

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Problem 41PS

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Experiment4: Solubility Product In the experiment to determine the solubility of KI04, in water, the following observations are made at a certain temperature: Volume of saturated KI04 solution taken in the conical flask = 25.0 mL KI added=2g H2SO4 (3.0 M ) added = 20.0 mL. Volume of 0.200M sodium thiosulphate used for titration = 8.00 mL Q1.If the mean ionic activity coefficient, γ± of KIO4 in the saturated solution is 0.85, what is Ksp of KIO4.?
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VIII. A primary standard of HCI is sodium carbonate, Na2CO3. A measured mass of solid Na2CO3, mNa2CO3' in grams, is dissolved in water and then titrated with HCI solution using methyl 2 NaCl + CO2 + H2O. orange indicator. The reaction is: Na2CO3 + 2 HCI- Complete the following formulas using the context described above: MHCI × VHCI in mL at the methyl orange endpoint = mNa2CO3 × ( )= mol of Na2CO3 mol of Na2CO3 X (— ( - - )= mol of HCl
Hh.132.
7. (8 pts) Calculate the solubility product, Ksp, for SrF2, given that its solubility is 0.0080 g per 225.0 mL of solution. SrF (s)  Sr2 (aq)  2F  (aq) 2
Given are the following reactions: Reaction #1 N2H4(l)+O2(g)⟶N2(g)+2H2O(g) ΔH⊖reaction= -534.2 kJkJ Reaction #2 H2(g)+1/2O2(g)⟶H2O(g) ΔH⊖reaction = -241.8 k a. what is the reversed reactions equation? b. what is delta h of the reversed reaction?
Help with the CHEM Lab report please! It is about Volumetric Analysis There is also a Burn trail please make sure for that!
3 Bal, (aq)+ 2 Nag POq Caq) 7 BalPO42 + l6 Nal laq • Consider the reaction of 30.0mL of 0.270M Balz with 20.0 mL of 0.3ISM Naz PO4. Lwhat quantity in meles of Balz are preset in the solution? are produced /What quantitg in moles of precipitate E ali Bal were consumed based on the balanced chomical equation? 6) What auantity in males of Na3 Pla aro present in soluction? d) What quantity in moles of precipitate are paduced if all the Naz PO, were cansumed based on the balanced chemi.cal equation? e) which reactant is limisting f What mass (in g) of precipitate is firemed when the limiting reactant is considered?
Gravimetric analysis of Fe3O4 (MW = 232 g/mole) may be undertaken with the following reactions: Fe3O4 → Fe2O3 → Fe (OH)3. Weight of sample containing 8.00% Fe3O4 that must be taken to obtain a precipitate of Fe(OH)3 (MW = 107 g/mole) that weighs 150 mg is . a. 0.108 g b. 0.325 g c. 1.355 g d. 4.065 g Amount of Fe2O3 (MW = 160 g/mole) from which 150 mg of Fe(OH)3 (MW = 107 g/mole) may be obtained is . a. 0.112 g b. 0.224 g c. 0.448 g d. none of the other choices
4. Predict the effect of temperature decrease, (b) pressure increase, (c) concentration increase of O2 on the concentration of all species. Answer using "more" or "less". 2 SO3(9) O2(9) + 2 SO2(9) AH = - 47 Kcal a. b. С.
A 0.2500-g of dry CaCO3 was completely dissolved into a solution of 5-mL conc. HCl and 50-mL distilled water in an erlemeyer flask. The resulting solution was boiled for 5 minutes to expel CO2 from the reaction, and then it was cooled to room temperature and the solution was transferred in a 500-mL volumetric flask filled to volume by rinsing the erlenmeyer flask and combining all the washings to fill the mark. A 5.0-mL aliquot of the CaCl2 solution was taken from the orignal solution and was transferred into an erlenmeyer flask with 10-mL NH3 buffer, 20-mL distilled water, and 5 gtts of EBT. The solution consumed 4.96 mL of an EDTA solution. MW: CaCO3 = 100.1 Compute for the N EDTA solution. 0.0053 N 0.0531 N 0.5313 N None of the choices

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